Is this proportional or nonpoportional?

a farmer enough to last his 40 cattle for 35 days'if he bays more cattle how long can the same food last?consider the cattle fin

Lapatulllka [165]

Answer:

this is unclear

Step-by-step explanation:

yoy miss typed

7 0

2 years ago

Express M=cos3A + cos A and N = sin3A + sin A as a product form

elena-14-01-66 [18.8K]

Answer:

2cosAcos2A, 4sinAcos^2A

Step-by-step explanation:

cos3A+cosA

2cos((3A+A)/2)cos((3A-A)/2)

2cos(4A/2)cos(2A/2)

2cosAcos2A

sin3A+sinA

2sin((3A+A)/2)cos((3A-A)/2)

2sin(4A/2)cos(2A/2)

2sin2AcosA

4sinAcos^2A

3 0

2 years ago

What is the value of x in the proportion below? 57=x21

Rama09 [41]

Answer:

2.71428571429

Step-by-step explanation:

calculator, counted it myself too to check if it's right

2.71428571429

PLEASE VOTE 5.0 MARK ME BRAINLIEST AND THANK ME

8 0

3 years ago

Read 2 more answers

Name the angle relationship.

Korolek [52]

They’re vertical angles!

6 0

3 years ago

The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability

Whitepunk [10]

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let Y = the time taken to deliver a pizza.

The random variable Y follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

$f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.$

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

$P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70$

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let X = results of a certain blood test.

It is provided that the random variable X follows a Normal distribution with parameters $\mu = 60$ and $s = 18$ .

The probabilities of a Normal distribution are computed by converting the raw scores to z-scores.

The z-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

$P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z$

The percentage of results more than 45 is: $0.7967\times100=79.67\%$

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

$P(X$

The percentage of results less than 85 is: $0.9177\times100=91.77\%$

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

$P(75$

The percentage of results are between 75 and 90 is: $0.1558\times100=15.58\%$

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

$P(20$

Then the probability that the results outside the range 20 to 100 is: $1-0.9736=0.0264$ .

The percentage of results outside the range 20 to 100 is: $0.0264\times100=2.64\%$

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

4 0

3 years ago

Is this proportional or nonpoportional?​

Is this proportional or nonpoportional?