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3 years ago

Subtract. –5.8 – (–8.4) A. –14.2 B. –2.6 C. 2.6 D. 14.2

2 answers:

6 0

-5.8 - (-8.4)

When we multiply two negatives they become a positive. In this situation, where there is no other number, you can assume there's basically a 1 in that place.

-5.8 - 1(-8.4) would be just as correct. (If this helps visually clarify anything.)

So we take that -1 and multiply it by that -8.4. Multiplying 1 against anything leaves it the same, so we just need to change the sign. Two negatives make a positive.

-5.8 + 8.4

Now we add these together.

This gives us our final answer of 2.6

Dominik [7]3 years ago

4 0

-5.8-(8.4) negative sign before ( ) change the sign of all term inside the ( ) -5,8+8.4= 2,6 C, 2.6 hope this helps

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Point C is between D and E and DE = 91 what is DC?

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Answer:

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Step-by-step explanation:

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2 years ago

If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the

denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

$\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)$

Now at head wind → $720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)$

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

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3 years ago

What is the fewest number of distinct points that must be graphed?

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Answer:

Step-by-step explanation:

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2 years ago

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3 years ago

A tiling company completes two jobs. The first job has $1200 in labor expenses for 40 hours worked, while the second job has $15

daser333 [38]

Answer:

The correct option is;

1560 = 30(52) + b

Step-by-step explanation:

The cost of the first job = $1,200 in labor and expenses

The number of hours worked in the first job = 40

The second job costs $1,560 in labor and expenses

The number of hours worked in the second job = 52

If the cost of labor per hour = L and the expenses = b, we have;

$1,200 = 40×L + b......................(1)

$1,560 = 52×L + b.......................(2)

Subtracting equation (1) from (2), we have;

52×L + b - (40×L + b) = 52×L - 40×L + b - b = $1,560 - $1,200 = $360

12×L = $360

L = $360/12 = $30/hour

From equation (1), we have;

$1,200 = 40×L + X = 40×$30 + b

Therefore, the equation that can be used to calculate the y-intercept of the linear equation is either;

1200 = 40(30) + X or 1560 = 32(52) + b, which gives the correct option as 1560 = 32(52) + b

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2 years ago