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alukav5142 [94]
3 years ago
14

Please help Algebra . ASAP

Mathematics
1 answer:
Norma-Jean [14]3 years ago
8 0
4 different salads, 7 different main courses, and 6 different desserts
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The perimeter of a triangle is 88. The sides have lengths d, e, and f. The ratio of e to d is 3:1, and the ratio of f to e is 10
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30039283 d

Step-by-step explanation:

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A car enthusiast learns that a particular model of car, which costs $34,411 new, loses 25% of its value every year. How much wil
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Arrie is planning her birthday party at a restaurant. She cannot spend more than $75 on the party. The cost per person for the m
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A. 5

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3 years ago
The perimeter of a rectangular carpet is 48 inches. It’s length is 2 meters larger than its width. Find its length
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Answer:

Length = 11 meters

Step-by-step explanation:

( x + 2 ) + ( x + 2 ) + x + x = 48

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     - 4     - 4

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3 years ago
A company has 125 personal computers. The probability that any one of them will require repair on a given day is 0.025. To find
Ostrovityanka [42]

Answer:

Binomial probability

P(X = 20) = C_{125,20}.(0.025)^{20}.(0.975)^{95}

Step-by-step explanation:

For each computer, there are only two possible outcomes. Either they fail, or they do not. The probability of a computer failing is independent from the probability of other computers failing. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 125, p = 0.025

To find the probability that exactly 20 of the computers will require repair on a given day, one will use what type of probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 20) = C_{125,20}.(0.025)^{20}.(0.975)^{95}

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3 years ago
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