Answer:
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Step-by-step explanation:
A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?
Let
x = number of tickets sold for $26
y = number of tickets sold for $40
x + y = 6000
x = 6000 - y
$26 × x + $40 × y= $185, 400
26x + 40y = 185400
Substitute
26(6000 - y) + 40y = 185400
156000 - 26y + 40y = 185400
Collect like terms
- 26y + 40y = 185400 - 156000
14y = 29400
y = 29400/14
y = 2100 tickets
x = 6000 - y
x = 6000 - 2100
x = 3900 tickets
Hence
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Answer:
Step-by-step explanation:
Divide the total number of cans (5022) by the number of homerooms (18) to get the number of cans collected by each homeroom:
5022 cans
---------------------- = 279 cans per homeroom
18 homerooms
Answer:
C(t)=3000(1.002417)^12t+960t
if T=1 year then the saving will be : 4048.17
Step-by-step explanation:
3000 deposit amount, 2.9 compound monthly interest . save 80 dollars per month at home .
A=p(1+r)^t
A=3000(1+0.029/12)^12t
A=3000(1.002417)^12t dollars
for the amount saved at home=80*12t=960t dollars
C(t)=3000(1.002417)^12t+960t
if T=1 year then the saving will be :
C(t)=3000(1.002417)^12t+960t
=3088.17+960= 4048.17 dollars
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)