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xxTIMURxx [149]
3 years ago
15

If anyone can help me with this geometry homework i will give you 80 dollars like fr on everything NO LINKKSS!!

Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0
Whats the geometry homework
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A sprinter can run 279 feet in 9 seconds. Find the sprinter's unit rate of feet per second.
Lorico [155]
The answer is 31 feet per second :)
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3 years ago
Solve 5x-y=5 and 2y-x^2=11 without using trial improvement
iren2701 [21]

Answer:

x = 7, y = 30  and  x = 3, y = 10

Step-by-step explanation:

5x - y = 5, then y = 5x - 5

2y - x^2 = 11

2(5x - 5) - x^2 = 11

10x - 10 - x^2 = 11

-x^2 + 10x -10 = 11

-x^2 + 10x -21 = 0

x^2 - 10x + 21 = 0

(x - 7)(x - 3) = 0

x = 7, y = 30

x = 3, y = 10

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3 years ago
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They charge the same amount in 5 hours.
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3 years ago
Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)
Elis [28]

Answer:

Distance between point (3,4) and midpoint of line joining (8,10) and (4,6) = 5 units.

Step-by-step explanation:

Given:

Points:

A(3,4)\\B(8,10)\\C(4,6)

To find distance from point A to midpoint of  BC.

Midpoint M of BC:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\

M=(\frac{8+4}{2},\frac{10+6}{2})\\     [Plugging in points B(8,10)\ and\ C(4,6)]

M=(\frac{12}{2},\frac{16}{2})\\

M=(6,8)\\

Distance between A and M:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

D=\sqrt{(6-3)^2+(8-4)^2} \\   [Plugging in points A(3,4)\ and\ M(6,8)]

D=\sqrt{(3)^2+(4)^2} \\

D=\sqrt{9+16} \\

D=\sqrt{25} \\

D=\pm5

Since distance is always positive ∴ D= 5 units

4 0
3 years ago
What are 3 like terms for -19m
Lyrx [107]

Answer:

isn't there a problem to this ?

Step-by-step explanation:

7 0
3 years ago
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