What is the common ratio of the following sequence?

Mathematics

2 answers:

andrew-mc [135]2 years ago

6 0

The answer is “c. 4” because each interval is being multiplied by 4

boyakko [2]2 years ago

4 0

$\text{Hello there!}\\\\\text{We're trying to find the common ratio}\\\text{The common ratio is the number that the sequence is changing by}\\\\\text{To find the common ratio, we need to find how much the sequence is}\\\text{changing by}\\\\\text{From -5 to -20, we know that it's multiplying by 4}\\\\\text{From -20 to -80, it's multiplying by 4}\\\\\text{Therefore, our common ratio is 4}\\\\\large\boxed{\text{Answer: C.\,\,4}}$

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Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

8 0

3 years ago

Last one I have to do!

Maksim231197 [3]

Answer:

one Square wide and 5 high

Step-by-step explanation:

5 0

3 years ago

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Lena [83]