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SashulF [63]
3 years ago
15

Kendra was asked to find the number of students who planned to attend the evening symphony performance. She was told that 40 per

cent of the 50 students planned to attend. Kendra’s work is shown below.

Mathematics
1 answer:
asambeis [7]3 years ago
3 0

Answer:

Kendra should of divided by 2

Step-by-step explanation:

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Ms. Carey grades 4 tests during her lunch. She grades 1/3 of the remainder after school. If she syill5has 16 test to grade after
enot [183]

Answer: 24 tests

Step-by-step explanation:

Ms. Carey graded 1/3 of the tests and still had 16 tests to go.

This means that the 16 tests represent the remaining proportion of the total number of tests:

= 1 - 1/3

= 2/3

2/3 of the total is equal to 16 tests. Assuming the total is x, the expression would be:

2/3x = 16

x = 16 ÷ 2/3

x = 16 * 3/2

x = 24 tests

3 0
3 years ago
Solve for m.<br> m+9=-2<br><br> m=?
amm1812
11
subtract 9 to both sides
7 0
3 years ago
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Round your answer to the nearest hundredth.<br> с<br> B<br> 40°<br> ?<br> 7<br> А
igor_vitrenko [27]

Answer:

take 40 degree as reference angle

using sine rule

let opposite be x

sine 40=opposite/hypotenuse

0.64=x/7

0.64*7=x

4.48=x

Step-by-step explanation:

3 0
3 years ago
Choose the best answer:
Oksi-84 [34.3K]

Answer:

The length of the hypotenuse is 2 square root of 13 ⇒ c

Step-by-step explanation:

The rule of the area of the right triangle is A = \frac{1}{2} × leg1 × leg2, where

leg1 and leg2 are the sides of the right angle

∵ The area of a right triangle is 12 in²

∵ The ratio of the length of its legs is 2: 3

→ Let leg1 = 2x and leg2 = 3x

∵ leg1 = 2x and leg2 = 3x

→ Substitute them in the rule of the area above

∴ 12 = \frac{1}{2} × 2x × 3x

∵ 2x × 3x = 6x²

∴ 12 =  \frac{1}{2} × 6x²

∴ 12 = 3x²

→ Divide both sides by 3 to find x²

∴ 4 = x²

→ Take √ for both sides

∴ x = 2

→ Substitute x in the expressions of leg1 and leg2 to find them

∴ leg1 = 2(2) = 4 inches

∴ leg2 = 3(2) = 6 inches

∵ hypotenuse = \sqrt{(leg1)^{2}+(leg2)^{2}}

∴ hypotenuse = \sqrt{(4)^{2}+(6)^{2}}=\sqrt{16+36}=\sqrt{52}

∵ The simplest form of \sqrt{52} = 2\sqrt{13}

∴ The length of the hypotenuse = 2\sqrt{13} inches

3 0
3 years ago
**NEED ANSWER ASAP** write an equation of a line that passes through the x-intercept 4 with slope -3
Svet_ta [14]

Answer:

y=4x+-3 is your equation

7 0
2 years ago
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