Answer:
36
Step-by-step explanation:
Answer:
18.0167≤x≤21.9833
Step-by-step explanation:
Given the following
sample size n = 10
standard deviation s = 3.2
Sample mean = 20
z-score at 95% = 1.96
Confidence Interval = x ± z×s/√n
Confidence Interval = 20 ± 1.96×3.2/√10
Confidence Interval = 20 ± (1.96×3.2/3.16)
Confidence Interval = 20 ± (1.96×1.0119)
Confidence Interval = 20 ± 1.9833
CI = {20-1.9833, 20+1.9833}
CI = {18.0167, 21.9833}
Hence the required confidence interval is 18.0167≤x≤21.9833
Answer:
1st answer is in the pic
2nd answer is that there are
1650 childs and 550 adults
Step-by-step explanation: the picture
If you want the 1st answer in words, it is here
Correct result:
a = 100
c = 800
t = 300
Solution:
6a + 5t + 4c = 5300
a + t + c = 1200
(8/3)t = c
6•a + 5•t + 4•c = 5300
a + t + c = 1200
(8/3)•t = c
6a+4c+5t = 5300
a+c+t = 1200
3c-8t = 0
a = 100
c = 800
t = 300
1 + 1 equals 2
check:
2 - 1 = 1