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Katyanochek1 [597]
3 years ago
11

sam and james win £500 in a competition. they share the money 3:7. sam gives 35% of the money he wins to his brother, harry. how

much money does harry receive?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0
Sam gets (500/10)*3=150<span>£
harry gets (150/100)*35= 52.5</span>£
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-28xy - ( - 4yz ) - ( - 4yx ) - 2zy =
ziro4ka [17]

Answer:

-24xy+2yz

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7 0
3 years ago
In quadrilateral DBCA, name the angles which are consecutive with angle D.
lisov135 [29]

Answer: The consecutive angles with angle D are B and A.

Explanation:

It is given that DBCA is a quadrilateral. Since it is a quadrilateral it means the have 4 vertices and 4 angles D, B,C,A.

The angles are formed in the order of the figure name. If the quadrilateral name is DBCA, So the order of the angles are D,B,C,A. It means the angle immediate after D is B, the angle immediate after B is C, the angle immediate after C is A and the angle immediate after A is D.

If the quadrilateral name is DBCA it means the sides are DB, BC, CA and AD as shown in the figure.

Consecutive angles of D means the angle immediate before and after the angle D.

In the figure there are some types of quadrilateral and from the figure we can easily noticed that the consecutive angles with angle D are B and A.

3 0
3 years ago
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During a snowstorm, 4 -1/2 inches of snow fell in 1 -1/3 hours. The same amount of snow fell each hour.
Marina CMI [18]
4 1/2 inches of snow
3 0
3 years ago
Please help me ASAP! Triangle ABC is located at A (2, 3), B (4, 4), and C (6, 3). Zackary says that triangle ABC is an isosceles
son4ous [18]
<h2>Hello!</h2>

The answer is:

The second option,

Zackery, because AB=BC

<h2>Why?</h2>

To identify which type of triangle is the triangle formed by the given points, first, we need to calculate the distance between the points.

So, finding the distances we have:

From A to B: (2,3) and (4,4)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(4-2)^{2} +(4-3)^{2}}=\sqrt{2^{2} +1^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

From B to C: (4,4) and (6,3)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(6-4)^{2} +(3-4)^{2}}=\sqrt{2^{2} +(-1)^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

Hence, since the distances AB and BC are equal, the triangle is an isosceles triangle, so the answer is:

Zackery, because AB=BC

Have a nice day!

7 0
3 years ago
Look at the right-angled triangle ABC.
olga_2 [115]

Answer:

∠x = 90°

∠y = 58°

∠z = 32°

Step-by-step explanation:

he dimensions of the angles given are;

∠B = 32°

Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;

∠A = 90°

∠B + ∠C = 90° which gives

32° + ∠C = 90°

∠C = 58°

∠x + Interior angle of the square = 180° (Sum of angles on a straight line)

∠x + 90° = 180°

∠x = 90°

∠x + ∠y + 32° = 180° (Sum of angles in a triangle)

90° + ∠y + 32° = 180°

∠y = 180 - 90° - 32° = 58°

∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)

58° + ∠z +90° = 180°

∴ ∠z = 32°

∠x = 90°

∠y = 58°

∠z = 32°

8 0
2 years ago
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