Answer:int x = 5;
if(x < 5)
cout << "line 1 ";
cout << "line 2";
A. line 1 line 2 B. line 1 C. line 2
D. line 1 E. line 1line 2
line 2
2. What would be output by the following code? _______
int x = 0;
while(x < 5)
{
cout << x << " ";
x++;
}
A. 0 1 2 3 4 5 B. 1 2 3 4 5 C. 0 1 2 3 4
D. 0 E. 0 0 0 0 0
3. After execution of the following code, what will be the value of input_value if the value 3 is entered at the keyboard at run time? ________
cin >> input_value;
if (input_value > 5)
input_value = input_value + 5;
else if (input_value > 2)
input_value = input_value + 10;
else
input_value = input_value + 15;
a. A. 8
b. B. 13
c. C. 18
d. D. 0
e. E. 5
4. What would the user see displayed on the screen after the following lines of code are executed?¬¬________
int i = 6;
if (i == 10)
cout << “value: “ << i;
else
cout << "hmmm";
A. value: i B. value: 10
C. hmmm D. value: ihmmm
E. value: 10
Hmmm
5. What is the output of the following lines of code? ______
for(int i=0; i<4; i++)
cout << (i * 3) << " ";
A. 0 1 2 3 4 B. 0 3 6 9
C. 0 3 6 9 12 D. 0 1 2 3 E. 0 0 0 0
Explanation:
True they would not start to use a product if it would not work
Hope this helps please mark this as brainliest answer
Answer:
101.1
Explanation:
Keep in mind that octal has 8 numbers
Step 1: Split your number in 2 parts (integer part and decimal part):
- integer part 65
- decimal part 0.125
Step 2: Convert the decimal part. For this step you need to multiply your decimal part and 8 (8 correspond the octal base) and get the integer part until you need it:
0.125 * 8 = 1
So your decimal part correspond to number 1 in octal = (1)8
Step 3: Convert integer part: for this step you need to divide your integer part by 8 until you can and get the remainder
65 / 8 = 8 remainder 1
8 / 8 = 1 remainder 0
1 / 8 = 0 remainder 1
Step 4: join the remainders from bottom to top and get the integer part
101
Step 5: join the integer part and the decimal part to get the octal convertion
101.1
I believe it's B.) Printer and Faxes.
