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3 years ago

Find the equation of the line that is perpendicular to y = –3x + 1 and passes though the point (6, 3).

Mathematics

1 answer:

noname [10]3 years ago

6 0

Answer:

A. y=1/3x+1

Step-by-step explanation:

When finding a line that is perpendicular to another line, all you have to do is find the "opposite reciprocal" of the slope. In this case that means writing the slope as the fraction -3/1, and then flipping the fraction over (1/-3) and taking away the negative sign which gets you 1/3 for the slope of your new line. Now, all you have of your new equation is the slope. You need to take your new equation (y=1/3x+b) and plug in the x and y coordinates to that equation, and then solve for the last variable which is b. That solving process goes as follows:

3=1/3*6+b

3=2+b

1=b

now you can replace the b with 1 in your equation to get your final answer of y=1/3x+1

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What is the equation of the line that passes through (-3, -1) and has a slope of 2/5? Put your answer in slope-intercept form.

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Hi there!

The general formula of A line in slope-intercept form is the following:
$y = mx + n$

In this formula m represents the slope of the line. Therefore, we can conclude that m = 2/5.
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Multiply first.
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And finally add 1 1/5 to both sides of the equation.
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We can now switch sides.
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Now we've found our value of n, which we can substitute into the formula of our line. Hence, in slope-intercept form, we find the following:
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