The probability that first a red bead is drawn and next a blue bead is drawn is 7/30,and both events are dependent
<h3>How to determine the probability?</h3>
The distribution of the beads are:
Red = 3
Blue = 7
Total = 10
The probability of selecting the red bead first is:
P(Red) = 3/10
When the red bead is selected, the number of beads becomes 9
So, the probability of selecting a blue bead is
P(Blue) = 7/9
The probability of the event is then calculated using:
P = 3/10 * 7/9
Evaluate
P = 7/30
Hence, the probability of the event is 7/30
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Answer:
- -28y^4 - 7y^3 + 62y^2 + 5y - 30
Step-by-step explanation:
<u>Opening the parenthesis and simplifying by combining like terms:</u>
- (6 - y - 4y^2)(-5 + 7y^2) =
- 6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
- -30 + 42y^2 + 5y - 7y^3 +20y^2 -28y^4 =
- -28y^4 - 7y^3 + 62y^2 + 5y - 30
I think its D i got 23 but 24 is the closes
This fraction cannot be changed to a mixed number because 3 can divide 42 to give 14. Hope i helped. Have a nice day.
The answer to this question is C
