Answer:
The pencil cost $0.05 and the pen cost $1.05.
Step-by-step explanation:
Let, the price of the pencil is $ .
Given that the pen costs a dollar more than the pencil,
So, the price of the pen=$+1.
Therefore, ++1=1.10
, 2+1=1.10
, 2=1.10–1
, 2=0.10
, =0.10/2
, =0.05
The pencil cost $0.05 and the pen cost $1.05.
Answer:
9x^4-25x^2+16
Step-by-step explanation:
(x^2−1)(3x−4)(3x+4)=(*)
(x^2−1)((3x)^2−4^2) =
(x^2 - 1)(9x^2-16)=
x^2*9x^2 - x^2*16 - 1*9x^2 +16=
9x^4-16x^2-9x^2+16=
9x^4-25x^2+16
(*) (A-B)(A+B) =A^2 - B^2
Answer:
(a) The sample sizes are 6787.
(b) The sample sizes are 6666.
Step-by-step explanation:
(a)
The information provided is:
Confidence level = 98%
MOE = 0.02
n₁ = n₂ = n
Compute the sample sizes as follows:
Thus, the sample sizes are 6787.
(b)
Now it is provided that:
Compute the sample size as follows:
![n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%28z_%7B%5Calpha%2F2%7D%29%5E%7B2%7D%5Ctimes%20%5B%5Chat%20p_%7B1%7D%281-%5Chat%20p_%7B1%7D%29%2B%5Chat%20p_%7B2%7D%281-%5Chat%20p_%7B2%7D%29%5D%7D%7BMOE%5E%7B2%7D%7D)
![=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2.33%5E%7B2%7D%5Ctimes%20%5B0.45%281-0.45%29%2B0.58%281-0.58%29%5D%7D%7B0.02%5E%7B2%7D%7D%5C%5C%5C%5C%3D6665.331975%5C%5C%5C%5C%5Capprox%206666)
Thus, the sample sizes are 6666.
Answer: Minimum: 20
Quartile Q1: 23.5
Median: 27
Quartile Q3: 31
Maximum: 35
Step-by-step explanation: The five number summary gives you a rough idea about what your data set looks like. For example, you’ll have your lowest value (the minimum) and the highest value (the maximum) or where data is more concentraced. The main reason you’ll want to find a five-number summary is to find more useful statistics, like the interquartile range IQR, sometimes called the middle fifty.
