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3 years ago

Help asap!!!!!!!!!!!

Mathematics

1 answer:

svlad2 [7]3 years ago

3 0

Answer:

The answer to your question is:

Step-by-step explanation:

12.-

x² - 6x = 5

x² - 6x + (3)² = 5 + (3)²

x² - 6x + 9 = 5 + 9

(x - 3)² = 14

13.- x² - 6x = 12

x² - 6x + (3)² = 12 + (3)²

x² - 6x + 9 = 12 + 9

(x - 3)² = 21

x - 3 = ±√21

x1 = √21 + 3 x2 = -√21 + 3

x1 = 7.58 x2 = -1.58

14.- 2x² - 24x = - 20 Divide by 2

x² - 12 x = -10

x² - 12x + (6)² = - 10 + (6)²

x² - 12x + 36 = - 10 + 36

( x - 6) ² = 26

x - 6 = ±√26

x1 = √26 + 6 x2 = -√26 + 6

x1 = 11.1 x2 = 0.9

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13/3 is 4 1/3

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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2 years ago

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3 years ago

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6.3 The daily amount of coffee, in liters, dispensed by a machine located in an airport lobby is a random variable X having a co

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Answer:

a) 60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

b) 70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

c) 50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

The probability of X being higher than x is:

$P(X > x) = 1 - \frac{x - a}{b-a}$

The probability of X being between c and d is:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

For this problem, we have that:

$a = 7, b = 10$

(a) at most 8.8 liters;

$P(X \leq 8.8) = \frac{8.8 - 7}{10 - 7} = 0.6$

60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

(b) more than 7.4 liters but less than 9.5 liters;

$P(7.4 \leq X \leq 9.5) = \frac{9.5 - 7.4}{10 - 7} = 0.7$

70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

(c) at least 8.5 liters.

$P(X > 8.5) = 1 - \frac{8.5 - 7}{10 - 7} = 0.5$

50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

3 0

3 years ago