Answer:
Hello,
I have reply too quick in comments (sorry)
Step-by-step explanation:
![\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dlog_x%20%2827%29%2Blog_y%20%284%29%3D5%5C%5Clog_x%20%2827%29-log_y%20%284%29%3D1%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D2%2Alog_x%20%2827%29%3D6%5C%5C2%2Alog_y%20%284%29%3D4%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dlog_x%20%2827%29%3D3%5C%5Clog_y%20%284%29%3D2%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dx%5E%7Blog_x%20%2827%29%7D%3Dx%5E3%5C%5Cy%5E%7Blog_y%20%284%29%7D%3Dy%5E2%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D27%3Dx%5E3%5C%5C4%3Dy%5E2%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C%5C%5C%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dx%3D3%5C%5Cy%3D2%5C%5C%5Cend%7Barray%7D%5Cright.%5C%5C%5C%5C)
Answer: The simplest form of ratio 6:15=2×3:5×3=2:5
Step-by-step explanation: So, 2:5 is equivalent to 6:15.
I don't think it can be reduced anymore.
Use the compound interest formula.
Let A = the ending amount
Let P = the principal
Let r = the interest rate
Let n = the amount compounded a year
Let t = time
A = P(1 + r/n) ^(n/t)
Substitute your numbers in
A = $7,000(1 + 0.06/4)^(4/7)
Solve for A
A = $7,059.81
Answer:
38 degrees
Step-by-step explanation:
this is an isosceles triangle, meaning that the base angles are congruent.
the total triangle is equal to 180
so the equation would be: x=180 - (71+71)
evaluate:
x=180-142
x=38 degrees
Hope this helps :)