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yaroslaw [1]
3 years ago
5

Help asap!!!!!!!!!!!

Mathematics
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

The answer to your question is:

Step-by-step explanation:

12.-

                x² - 6x = 5

                x² - 6x + (3)² = 5 + (3)²

               x² - 6x + 9 = 5 + 9

               (x - 3)² = 14

13.-           x² - 6x = 12

               x² - 6x + (3)² = 12 + (3)²

               x² - 6x + 9 = 12 + 9

              (x - 3)² = 21

              x - 3 = ±√21

             x1 = √21 + 3                     x2 = -√21 + 3

               x1 = 7.58                           x2 = -1.58

14.-           2x² - 24x = - 20            Divide by 2

                x² - 12 x = -10

               x² - 12x + (6)² = - 10 + (6)²

               x² - 12x + 36 = - 10 + 36

              ( x - 6) ² = 26

               x - 6 = ±√26

x1 = √26 + 6                                 x2 = -√26 + 6

x1 = 11.1                                          x2 = 0.9

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The formula for the area of the shaded region in the figure.

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Generally, the equation for the Area is mathematically given as

& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\

&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h

A=\frac{8}{3} \sqrt{p h} \cdot h

In conclusion,  the equation for the Area is

   

A=\frac{8}{3} \sqrt{p h} \cdot h

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