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OverLord2011 [107]
2 years ago
5

The perimeter of a rectangle deck is 175 feet.The length of the deck,L, is 6 feet longer than 2 times the width, w. Determine th

e length and width, in feet, of the deck.
Mathematics
1 answer:
givi [52]2 years ago
8 0
x-\ length\\y-\ width\\\\
Perimeter=2x+2y\\\\
175=2x+2y\\
x=2y+6\\\\
175=2(2y+6)+2y\\
175=4y+12+2y\\
175=6y+12\ \ \ |Subtract\ 12\\
163=6y\ \ \ |Divide\ by\ 6\\
y=27,17feet\\\\
x=2*27,17+6=60,34feet\\\\
Length=60,34 \ feet\ and\ width=27,17\ feet.
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The perimeter of a rectangle is 102 inches. The length is 5 inches greater than the width.
Mazyrski [523]

Answer:

w = 23

l = 28

Step-by-step explanation:

w = width

l = w+5

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3 years ago
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Answer:

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Step-by-step explanation:

We can create a triangle from the information given.

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<em><u>See the attached picture. The direct distance is labeled as x.</u></em>


Now we need to find x using pythagorean theorem.

Pythagorean Theorem = leg²+leg²=hypotenuse²

Solving for x:

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<em>Rounding to nearest tenth, we have </em><em>11.2 miles</em>

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2 years ago
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