Question

The perimeter of a rectangle deck is 175 feet.The length of the deck,L, is 6 feet longer than 2 times the width, w. Determine the length and width, in feet, of the deck.

Answer 1

$x-\ length\\y-\ width\\\\ Perimeter=2x+2y\\\\ 175=2x+2y\\ x=2y+6\\\\ 175=2(2y+6)+2y\\ 175=4y+12+2y\\ 175=6y+12\ \ \ |Subtract\ 12\\ 163=6y\ \ \ |Divide\ by\ 6\\ y=27,17feet\\\\ x=2*27,17+6=60,34feet\\\\ Length=60,34 \ feet\ and\ width=27,17\ feet.$