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Svetach [21]
4 years ago
15

there are 146 students taking buses to the museum.if each bus holds 24 students,how many buses will they need?

Mathematics
1 answer:
Alex_Xolod [135]4 years ago
7 0
146/24=6.08333 buses are needed.
But this 0.08333 means that there are 2 students left as a remainder. The first 6 busses are full, and 2 students are remaining outside. We cant leave them there! So we need another bus, which gives a total of 7 buses
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In a recipe for fizzy grape juice, the ratio of cups of sparkling water to cups of grape
Ierofanga [76]

ummm well thats a good question

Step-by-step explanation: hold on let me think

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3 0
3 years ago
Ben claims that 12 is a factor of 24.how can you check whether he is correct?
Anna71 [15]

Divide the  24  by Ben's  12 . 

If his  12  is a factor, then the division will come out even,
and the answer will be a whole number.

A).  6 x 4 = 24

B).  5 x 9 = 45

C).  3 x 8 = 24

D).  6 x 9 = 54

8 0
3 years ago
Children shorter than 54 inches get into the water park free. Howard is currently 42 inches tall. He grows approximately 3 inche
slava [35]

Answer:

42 + 3y ≤ 54

Step-by-step explanation:

6 0
3 years ago
The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
3 years ago
I am just completely lost and am unsure of how to approach this problem.
Anastasy [175]

Answer:

68°

Step-by-step explanation:

As BA⊥BD, so ∠ABD = 90°

also, ∠ABD = ∠CBD + ∠ABC

⇒ 90° = 4x + 52° + 8x - 10°

⇒  12x = 48°

⇒  x = 4°

now,

∠CBD = 4x + 52°

          = 4(4°) + 52°

          = 68°

5 0
3 years ago
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