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blagie [28]
3 years ago
12

Please help me i will give u brainliest if it is CORRECT

Mathematics
2 answers:
Oduvanchick [21]3 years ago
5 0
25% is the answer cause there are 4 part 100% of 4 is 25% for each
Rama09 [41]3 years ago
4 0
50 percent, 2 of the numbers are even numbers and there are 4 numbers in all
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I need help with this problem plzzz
Effectus [21]

Not sure sorry but you can. Try searching on google or yahoo answers

6 0
3 years ago
The mass of a rock sample is 25 g and
balu736 [363]

Answer:

given us,

mass= 25g

density= 5 g/ cm2

here,

volume = mass/ density

= 25g/ 5g cm2

= 5cm2

Step-by-step explanation:

cm2 is the square

3 0
3 years ago
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How many, and what type of, solutions does 4x² + 12x + 9 = 0 have? 2 irrational solutions 1 rational solution 2 nonreal solution
SVEN [57.7K]

The discriminant is

\sqrt{ {12}^{2}  - 4(4)(9)}

which is 0.

Since the discriminant is 0, there is only one real solution.

4 0
4 years ago
The Webb Institute offers free college tuition for those majoring in engineering. For fall 2015, 2 out of the 24 students who en
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Answer:

h

Step-by-step explanation:

6 0
3 years ago
In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th
WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ;   10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, \frac{dx}{dt} = $1,000

Now,

a) computers per household are

since,

mean income of  $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e \frac{dq}{dt}

\frac{dq}{dt} = \frac{d(0.3458 ln x - 3.045)}{dt}

or

\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0

on substituting the values, we get

\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000

or

= 0.01153 computers

6 0
3 years ago
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