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3 years ago

Solve for the perimeter and keep it in pi

Mathematics

1 answer:

galben [10]3 years ago

4 0

Answer:

24+6pi

Step-by-step explanation:

the sides on the left and right added up are

12+12=24.

the formula for perimeter of a circle is 2πr.

3 is the radius, making the equation

2π3 which is 6 pi.

for the top semicircle, the perimeter would be 6 pi divided by 2 because its a semicircle.

the bottom cut out half would also be 3 pi.

in total, we would have 24+3pi+3pi which would lead you to 24+6pi.

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3 years ago

julian want to buy a new ipod that costs $220. he goes into a store and sees that it is on sale and has a 35% discount. he will

tigry1 [53]

Answer:

The final cost for him is;

$\text{ \$154.44}$

Explanation:

Given that the ipod costs $220;

$C=\text{ \$220}$

The store gives a 35% discount, which means he will only pay 65% of the original cost;

$100\text{\%- 35\% = 65\%}$

The store price is;

$\begin{gathered} P=\text{ 65\% of \$220} \\ P=\frac{65}{100}\times\text{ \$220} \\ P=\text{ \$143} \end{gathered}$

Also he will need to pay additional 8% sales tax on the discounted price P;

$\begin{gathered} t=8\text{\% of P} \\ t=8\text{\% of \$143} \\ t=\frac{8}{100}\times\text{ \$143} \\ t=\text{ \$11.44} \end{gathered}$

The final cost he need to pay is the sum of the discounted price and the sales tax;

$\begin{gathered} F=P+t \\ F=\text{ \$143 + \$11.44} \\ F=\text{ \$154.44} \end{gathered}$

Therefore, the final cost for him is;

$\text{ \$154.44}$

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1 year ago

Hi, I need help. so pls help me.

antiseptic1488 [7]

Answer:

Step-by-step explanation:

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3 years ago

For a trapezoid, the midsegment is one-half of...

jekas [21]

Answer:

Step-by-step explanation:

Mathematically, the mid segment of a trapezoid is exactly the average of the 2 parallel bases

What this means is that to find the length of the trapezoid, we will need to find the average of the two parallel bases

Mathematically, this is same as adding the two bases and dividing the result by 2.

Hence we can say it is exactly one-half the length of the sum of the two parallel bases

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3 years ago