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avanturin [10]
3 years ago
10

Please help me thanks

Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0

Answer:

E

R

R

R

E

E

Step-by-step explanation:

explanation

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NEED HELP WITH THIS PROBLEM!!!!!!
zzz [600]

Answer:

  \displaystyle\frac{\sqrt[4]{3x^2}}{2y}

Step-by-step explanation:

It can work well to identify 4th powers under the radical, then remove them.

  \displaystyle\sqrt[4]{\frac{24x^6y}{128x^4y^5}}=\sqrt[4]{\frac{3x^2}{16y^4}}=\sqrt[4]{\frac{3x^2}{(2y)^4}}\\\\=\frac{\sqrt[4]{3x^2}}{2y}

_____

The applicable rules of exponents are ...

  1/a^b = a^-b

  (a^b)(a^c) = a^(b+c)

The x-factors simplify as ...

  x^6/x^4 = x^(6-4) = x^2

The y-factors simplify as ...

  y/y^5 = 1/y^(5-1) = 1/y^4

The constant factors simplify in the usual way:

  24/128 = (8·3)/(8·16) = 3/16

3 0
4 years ago
An article gave the following summary information for fracture strengths (MPa) of n = 196 ceramic bars fired in a particular kil
Oliga [24]

Answer:

54.80 MPa to 55.92 MPa

Step-by-step explanation:

Sample mean fracture strength (x) = 55.36 MPa

Sample standard deviation (s) = 3.99 MPa

Sample size (n) = 196.

The upper and lower bounds for a 95% confidence interval are given by:

U=x+1.960*\frac{s}{\sqrt{n}} \\L=x-1.960*\frac{s}{\sqrt{n}}

The upper and lower bounds of the confidence interval are;

U=55.36+1.960*\frac{3.99}{\sqrt{196}}\\U= 55.92\\L=55.36-1.960*\frac{3.99}{\sqrt{196}}\\L= 54.80\\

The 95% confidence interval for true average fracture strength is 54.80 MPa to 55.92 MPa

4 0
4 years ago
When 2/3 is added to a certain number, the sum is 3 greater than twice the number.
galina1969 [7]
3(2/3+n)=2n I believe
3 0
4 years ago
Simplify. 32 + 1 x 2 (1).8 (2).20 (3).14 (4).11​
pshichka [43]

Answer:

31.11

Step-by-step explanation:

simplify the expression

4 0
3 years ago
Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions
forsale [732]

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23  = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

y = 69-19

y = 50

If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

8 0
3 years ago
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