In the problem, how do you get 6,300,000 using the digits 1-7 to create a
seven-digit number that can be rounded to 6,300,000.
We can use the numbers according to the rule of rounding values, 0-4 and
5-9.
Hence the numbers are:
1. 6, 290,000 = 6, 300, 000
2. 6, 310, 000 = 6, 300, 000
Therefore the numbers concerned in the given value is in the place order of
ten thousand which will determine the hundred thousands’ value.
Multiply (length) times (width). For a square, both numbers will be the same.
Answer:
A
Step-by-step explanation:
1.95 + 1.09 = 3.04 so you will spend $3.04 then 5 - 3.04 = $1.96
Answer:
![[0, 3, -6]](https://tex.z-dn.net/?f=%5B0%2C%203%2C%20-6%5D)
Step-by-step explanation:
{4x + y = 3
{x + y - z = 9 ←
{2x + 2y + z = 0 ←
{4x + y = 3
{3x + 3y = 9 >> Combined equation
−¾[4x + y = 3]
{−3x - ¾y = −2¼ >> New Equation
{3x + 3y = 9
_________
2¼y = 6¾
___ ___
2¼ 2¼
[Plug this back into all three equations to get the z-value of −6, and the x-value of 0]; 
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I am joyous to assist you anytime.
