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Black_prince [1.1K]
2 years ago
12

I need help ASAP plz

Mathematics
2 answers:
Sladkaya [172]2 years ago
4 0
This is a right triangle. To find the third side of a right triangle. Use the Pythagorean Theorem.
a^2+b^2=c^2
a and b are the legs, c is the hypotenuse.
a^2+7^2=16^2
a^2+49=256
Subtract 49 from both sides:
a^2=207
Square foot:
a=14.38749457 in.
Round to nearest tenth:
14.4 in
Anit [1.1K]2 years ago
3 0

Answer:

a = 14.4

Step-by-step explanation:

It's a right angled triangle. so it has to follow Pythagoras Theorem

according to it square of hypotenuse = sum of squares of other two sides

16 {}^{2}   =  {x}^{2}  + 7 {}^{2}  \\ 256 = x {}^{2}  + 49 \\ 256 - 49 = x {}^{2} \\ 207 = x {}^{2} \\ x =  \sqrt{207 }  \\ x = 14.387 \\ x = 14.4

after rounding the decimal a= 14.4 in

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If a car traveled 162 miles in 3 hours, how many hours would it take to travel 351 miles? Please show work! :)
Flauer [41]

Answer:

390 minutes

Step-by-step explanation:

162 / 3 = 54

351 / 54 = 6.5

6.5 x 60 = 390 minutes

4 0
2 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
Math question thanks
dimulka [17.4K]

Using product and quotient property:

log x + log y can be displayed as log xy

Because we're subtracting 2 log z we can use the power property to rewrite this as log z^2

Now, using quotient property we can display this expression as:

<h3>log xy/z^2</h3>
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Step-by-step explanation:

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Answer:

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