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Tasya [4]
3 years ago
6

Solve

ormula1" title=" \frac{3}{5} + h = \frac{23}{5} " alt=" \frac{3}{5} + h = \frac{23}{5} " align="absmiddle" class="latex-formula">

solve. solve​
Mathematics
1 answer:
natali 33 [55]3 years ago
6 0

Step-by-step explanation:

Multyply 5/3 to 3/5. these cancel them out. Do the same to the other side (23/5)5/3

When you find the answer to (23/5)5/3,

It will be h=(that answer)

Please make this the brainlyest!

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Find the measure of each interior angle in a regular 18-gon
EastWind [94]

Answer:

A polygon with 18 sides has 18 interior angles. Therefore, to find the measure of one of these angles, divide the sum by 18. Answer: Each angle is 160 degrees.

Step-by-step explanation:

5 0
3 years ago
Help me please !!!!!!!!
777dan777 [17]

y=5/3x

this is because f(x)=x is one of (identity function) the 12 basic functions and when you multiply it it will shift it on the y axis

If you were to do y=x+5/3 it would make a horizontal shift to the left 5/3

So the unit your on is mostly about knowing the number located in the function that will make the graph shift different ways

8 0
4 years ago
How do you prove similarity in math?
ra1l [238]

Answer:

AA (Angle-Angle): If triangles have two of the same angles, then the triangles are similar. SAS (Side-Angle-Side): If triangles have two pairs of proportional sides and equal included angles, then the triangles are similar.

Step-by-step explanation:

3 0
1 year ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
Find the equation of a line with each of the following characteristics. a) parallel to the line y = 3x + 5 and has a y-intercept
Vedmedyk [2.9K]

Answer:

y = 1/2x - 1

Step-by-step explanation:

When you put all three equations from the question into a graph and then input the equation i just gave you it will be perpendicular to line B & C, also it will be parallel to line A. Finally you can check yourself that it also has a y-intercept of (0,-1) & an x-intercept of (2,0). Hopefully this helps out & gets brainliest. xD

4 0
3 years ago
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