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Elena L [17]
3 years ago
13

5x -6y = 0 what is the x-intercept

Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer:

0

Step-by-step explanation:

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240

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Find a function for the graph below
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A maritime flag is shown. What is the area of the shaded part of the flag? Explain
Rom4ik [11]

Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
3 years ago
What kind of question will ask us to use this type of format to evaluate the integral instead of doing the regular integral eval
ANEK [815]

Answer:

Great work!

Step-by-step explanation:

These kind of questions are calculated through Riemann Sum. You can evaluate any definite integral using the Riemann Sum. It should be in the following form:

f(x)dx on the interval [a, b], or

\int _a^b\:f\left(x\right)dx

Now f(x) is simply y. Therefore in this example y = x^3 - 6x. We just need the sufficient amount of data to apply the Riemann Sum, including the interval [a, b] that bounds the area, and the the number of rectangles 'n' that we need to use.

Consider an easier approach to this question: (First attachment)

Graph: (Second Attachment)

6 0
4 years ago
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