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Eddi Din [679]
3 years ago
14

Which graph represents an exponential growth function?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

Graph 1 or A

Step-by-step explanation:

The graph is gradually getting bigger as it starts at the left (0,-10) and gets bigger and bigger until it hits the end of the chart, increasing endlessly. That is exponential growth.

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Two walls have the same area. The first wall is in the shape of a square and has a height
STatiana [176]

Answer:

27 feet

Step-by-step explanation:

Two walls have same area

Area of first wall(square) = 18*18 = 324

Area of second wall = 12 * x = 324

324/12 = 27

27 feet

7 0
3 years ago
In an election, Candidate A received 75 votes and candidate B received 25 votes, after the first 100 votes were counted. Assume
enot [183]

Answer:

Candidate receives 2250 votes

Step-by-step explanation:

Ratio of votes A : B = 75 : 25  = 3 : 1

3 : 1 = x : 750

Product of means = Product of extremes

1 *x = 3*750

  x = 3 *750

     = 2250

3 0
2 years ago
NEED HELP! DUE TOMORROW 2/4/2021
m_a_m_a [10]
The second Version of the game is greater for hitting the down button because substituting any number for x, the second equation would always end up having a greater amount.
6 0
3 years ago
X2+y2=r2 Solve for y
Kaylis [27]

Answer: y=\sqrt{r^{2} -x^{2} }

Step-by-step explanation:

x^2+y^2=r^2 --> subtract x^2 to other side

y^2=r^2-x^2 --> square root both sides

y=sqrt(r^2-x^2)

3 0
2 years ago
When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval
Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

\alpha = 1-99%

  =1-0.99

  =0.01

then,

\frac{\alpha}{2} =\frac{0.01}{2}

  =0.005

or,

Z_{\frac{\alpha}{2} }=Z_{0.005}

     =2.576

Now,

The point estimate will be:

⇒  \hat{P}=\frac{x}{n}

⇒      =\frac{110}{343}

⇒      =0.321

or,

⇒  1-\hat{P}=1-0.321

⇒            =0.679

The margin of error will be:

⇒  E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )

On substituting the above values, we get

⇒      =2.576\times \sqrt{\frac{0.321\times 0.679}{343} }

⇒      =2.576\times \sqrt{\frac{0.217959}{343} }

⇒      =0.065

hence,

⇒  \hat{P}-E

⇒  0.321-0.065

⇒  0.256,0.386

6 0
3 years ago
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