Find the quotient. (6x 2 + 23x + 20) ÷ (5 + 2x)

Mathematics

2 answers:

arsen [322]2 years ago

8 0

Answer:

The quotient is 3x+4

Step-by-step explanation:

Given the dividend and divisor i.e we have to find the quotient if $6x^2+23x+20$ is divided by 5+2x

Given dividend is

$6x^2+23x+20$

⇒ $6x^2+15x+8x+20$

⇒ $3x(2x+5)+4(2x+5)$

⇒ $(3x+4)(2x+5)$

Hence, the given dividend can written in two factors.

Now, $\frac{6x^2+23x+20}{5+2x}=\frac{(3x+4)(2x+5)}{2x+5}=3x+4$

Hence, the quotient is 3x+4

tekilochka [14]2 years ago

4 0

<span>(3x -4)(2x-5) as this it is divided </span>

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2 years ago

The second term in a geometric sequence is 20. The fourth term in the same sequence is 45/4 or 11.25. What is the common ratio i

kati45 [8]

$\bf \begin{array}{ccll}
n&term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2&a_2&20\\
3&a_3&20r\\
4&a_4&20rr\\
&&20r^2\\\\
&&\frac{45}{4}
\end{array}\implies \stackrel{4^{th}~term}{20r^2=\cfrac{45}{4}}\implies r^2=\cfrac{45}{80}
\\\\\\
r^2=\stackrel{simplified}{\cfrac{9}{16}}\implies r=\sqrt{\cfrac{9}{16}}\implies r=\cfrac{\sqrt{9}}{\sqrt{16}}\implies r=\cfrac{3}{4}$