9514 1404 393
Answer:
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Step-by-step explanation:
The applicable derivative formula is ...
d(u/v) = (v·du -u·dv)/v²
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f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²
f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
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Similarly, the second derivative is the derivative of f'(x).
f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴
f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Answer:
sqrt(5)*sqrt(5)=5.
Step-by-step explanation:
X is 5 in this case!!!!hope it helps
Answer:
D
Step-by-step explanation:
The answer is point D(-2,1).
1. If the point D was moved down 2 units, then its coordinates became (-2,-1).
2. If point (-2,-1) was reflected over the x-axis, then its coordinates became (-2,1).
3. If the point (-2,1) was moved 4 units to the right, then its coordinates became (2,1).
4. If point (2,1) was reflected over y-axis, its coordinates became (-2,1).
Answer:
after reflection over y axis
a 9,7
b 9,6
c 0,6
d 0,7
