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Pavel [41]
3 years ago
12

Pls help i only have 4 pls and ty

Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

y= -1x+1

Step-by-step explanation:

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a carnival sold tickets for $1.50 for adults and $1.00 for students. there were 54 tickets sold for a total of $70.50. write a s
Likurg_2 [28]

Answer:

The number of adult tickets are 33 and the number of student tickets are 21 .

Step-by-step explanation:

As

The number of adult tickets x  and the number of student tickets y.

As given

A carnival sold tickets for $1.50 for adults and $1.00 for students.

There were 54 tickets sold for a total of $70.50.

Equations becomes

x + y = 54

1.50x + 1.00y = 54 × 70.50

Simplify the above

\frac{150x}{100} + \frac{100y}{100} = \frac{7050}{100}

150x + 100y =7050

Two equations are

x + y = 54

150x + 100y =7050

Multiply x + y = 54 by 150 from 150x + 100y =7050

150x - 150x + 100y - 150y = 7050 - 8100

-50y = -1050

50y = 1050

y = \frac{1050}{50}

y = 21

Putting the value of y in the equation .

x + 21 = 54

x = 54 - 21

x = 33

Therefore the number of adult tickets are 33 and the number of student tickets are 21 .

8 0
4 years ago
2/5 with an exponent of 3
ch4aika [34]

Answer:

2/5 with an exponent of 3 is 8/125 or 0.064

Step-by-step explanation:

Given:

A fraction = 2/5

Exponent = 3

To find the value of the fraction using the exponent.

We know that :

⇒ (a)^3=a\times a\times a  

The exponents is the number of times a number is multiplied.

So,

⇒ (\frac{2}{5})^3

⇒ \frac{2\times 2\times 2}{5\times 5\times 5}

⇒ \frac{8}{125}

On further division the number can be written as 0.064

5 0
3 years ago
Find the surface area
nlexa [21]

Answer:15

Step-by-step explanation:

i solved it!

7 0
3 years ago
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What is the approximate volume of a cone with a height of 9 ft and radius of 3 ft?
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Go on safari , && go to a circumference calculator , ion wanna explain rn .
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4 years ago
Anyone get this I need serious help!!
Lena [83]
It would be (-2,8). they are asking for the midpoint between point A and point B
3 0
3 years ago
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