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3 years ago

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The doubling time of a population of flies is 5 hours. By what factor does the population increase in 24 hours? By what factor d

oes the population increase in 3 weeks (504 hours)?
In exponential notation with positive exponents.

1 answer:

MrRa [10]3 years ago

4 0

Open this web,the web really help you http://www.math.wisc.edu/~meyer/math141/L25.html

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Write the polynomial in standard form. Identify the degree and leading coefficient of the polynomial. Then classify the polynomi

Musya8 [376]

Answer:

Standard form: 2c^4 + 6c^2 - c

Degree: 4th

Leading coefficient: 2

Classification: Trinomial

Step-by-step explanation:

In standard form, you have to put the term with the highest exponent first.

With finding the degree, you just look at the highest exponent and that's the degree. 4 is the highest exponent, so it is to the 4th degree.

The leading coefficient is the number attached to the highest exponent. 4 is the highest and the number attached to it is 2.

Classification goes by how many terms there are. Since there are 3, it's trinomial. Tri as in three.

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2 years ago

Why do graphs sometime not have a line through them?

kondaur [170]

If they do not have a line of best fit this may be because there is no correlation

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2 years ago

A line with a slope of 5 passes through the point (1,8). What is its equation in

Eduardwww [97]

Answer:

Step-by-step explanation:

In point-slope form, our equation would be y - 9 = 2(x - 1). Expanding, we get y - 9 = 2x - 2. Solving for y, we obtain the form of the equation as shown in the problem: y = 2x + 7.

So, the numbers that would go in the blanks would be 2 and 7, respectively.

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2 years ago

What does -2(3x-4)=8 mean??

Tom [10]

-2(3x-4)=8
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2 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

<u />

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

<u />

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

<u />

A similar problem is given at brainly.com/question/15683591

3 0

1 year ago