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kvasek [131]
3 years ago
9

What is the area of a triangle with a angle of 80 and a radius of 5

Mathematics
1 answer:
inysia [295]3 years ago
4 0
The formula for sector area is simple - multiply the central angle by the radius squared, and divide by 2: Sector Area = r² * α / 2.
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(-10, -7), (-8, 1)<br> Distance between
liubo4ka [24]

Answer:9

Step-by-step explanation

√(x2-x1)^2 +(y2-y1)^2

√(-7-(-10)^2 +(1-(-8)^2

√(-7+10)^2 + (1+8)^2

√(3)^2 +(9)^2

√(9+81)

√90

=9.48

Approximately 9

7 0
4 years ago
(please help me. ) (I screenshot the question and choices )
svlad2 [7]
Its A
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5 0
3 years ago
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What are the sum of the two pink angles?
jenyasd209 [6]

Answer:

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Step-by-step explanation:

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3 years ago
0.79 ( ) 0.7 which is greater
Alexxx [7]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
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What is the answer lol somebody help me please and thank you !
PilotLPTM [1.2K]

I'm guessing that you know about 45-45-90 and 30-60-90 triangles.

In 45-45-90 triangles, the legs are in a ratio such that the hypotenuse is \sqrt{2} times the legs.

In 30-60-90 triangles, the legs are in a ratio of 1:\sqrt{3}:2

In the picture given we have been given a value of the side of the 45-45-90 triangle. We can deduce that the value of the hypotenuse is 9\sqrt{2} because of the ratio of the sides of a 45-45-90 triangle.

The 30-60-90 triangle shares the same hypotenuse, and so we now know a value of one of its sides as well. The ratio of the side of value 'x' and the hypotenuse is \sqrt{3} : 2

We can create an equation to solve for x using these ratios:

\frac{\sqrt{3} }{2} = \frac{x}{9\sqrt{2} }

Cross multiply:

2x = 9\sqrt{6}

x = \frac{9\sqrt{6} }{2}

Option C

4 0
3 years ago
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