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Scrat [10]
3 years ago
5

A ladder is placed 8 feet away from a wall. The distance from the ground straight to the top of the wall is 16 feet. What is the

height of the ladder?

Mathematics
2 answers:
o-na [289]3 years ago
8 0

\boxed{\large{\bold{\blue{ANSWER~:) }}}}

<h2> Given:-</h2>

  • A ladder is placed 8 feet away from a wall. The distance from the ground straight to the top of the wall is 16 feet.

<h2>Find:-</h2>

  • What is the height of the ladder?

<h2>solution:-</h2>

A ladder is placed 8 feet away from a wall. The distance from the ground straight to the top of the wall is 16 feet.

so it is a right angle triangle

<h3>we know that, </h3>

in a right angle triangle, According to the Pythagorean theorom,

\boxed{\sf{l^2+b^2=h^2   }}

where

  • l= legs
  • b=base
  • h=hypotenuse

<h3>According to the question, </h3>
  • \sf{8^2+16^2=h^2   }

  • \sf{64+256=h^2   }

  • \sf{ h^2=320  }

  • \sf{h=\sqrt{320}   }

  • \sf{h=8\sqrt{5}  }

<h2>Therefore:-</h2>

The height of the ladder is \sf{8\sqrt{5}   }

elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

17.89 ft

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

8^2 +16^2 = c^2

64+ 256 = c^2

320 =c^2

Taking the square root of each side

sqrt(320) = sqrt(c^2)

sqrt(64*5) = c

sqrt(64) sqrt(5) =c

8 sqrt(5) = c

17.88854382=c

17.89 ft

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