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3 years ago

How to find the rate of a Change?

1 answer:

7 0

The correct answer is the vertical change<span> divided by the horizontal </span>change<span> between two points on a line. We can </span>find<span> the slope of a line on a graph by counting off the rise and the run between two points. If a line rises 4 units for every 1 unit that it runs, the slope is 4 divided by 1, or 4.</span>

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Please help me on number 3

Mars2501 [29]

circle=360°

360÷10=36

36÷3=12

Answer is 12

4 0

3 years ago

Please help me. This is due tomorrow

IRISSAK [1]

The picture is upside down my dude, delete the question, re-upload it and ill help you out.

3 0

3 years ago

Read 2 more answers

Determine whether the statement is true or false. If it is false, rewrite it as a true statement. A population is the collectio

tatuchka [14]

Answer:

False

Step-by-step explanation:

This is false because a population represents all and not some. A population is the collection of all outcomes, responses, measurements, or counts that are of interest. It is not a collection of 'some' outcomes. It is a collection of 'all' outcomes.

A population data set is a set which contains all the items or elements of a specified group or data set. It is a complete list of all the possible data values.

The sample of a population are drawn out of a population. They are A subset of a population.

8 0

3 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

3 years ago

Find the translation rule and the scale factor of the dilation that transforms Ol to Ol'.

lisov135 [29]

Answer:

C (x, y) -> (x + 7, y + 8); scale factor = 3

Step-by-step explanation:

The translation can be found by subtracting the coordinates of the original center from those of the center of the image. The scale factor will be the ratio of the radii.

<h3>translation</h3>

We note the center coordinates are I(-3, -6) and I'(4, 2). Then the translation is ...

I' -I = (4, 2) -(-3, -6) = (4 +3, 2 +6) = (7, 8)

(x, y) ⇒ (x +7, y +8)

<h3>scale factor</h3>

The radius of each circle can be found by counting the grid squares from the center to the circle. It works best to do this along a horizontal or vertical line.

The radius of circle I is 2; the radius of circle I' is 6. The scale factor is ...

scale factor = 6/2 = 3

4 0

2 years ago