Determine algebraically whether the function is even, odd, or neither even nor odd.
2 answers:
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<span>Part 1:
option b.
Part 2:
option d
Part 3:
Multiply through by the LCM of 2 and 3 (i.e. 6)
option b
Part 4
x^2-3x-8=x+4
option d
Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?
In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.
Therefore, he should add 16 to both sides because (8/2)^2=16.
option d.
</span>
option b.
Part 2:
option d
Part 3:
Multiply through by the LCM of 2 and 3 (i.e. 6)
option b
Part 4
x^2-3x-8=x+4
option d
Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?
In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.
Therefore, he should add 16 to both sides because (8/2)^2=16.
option d.
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