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mash [69]
3 years ago
15

Determine algebraically whether the function is even, odd, or neither even nor odd.

Mathematics
2 answers:
Nikolay [14]3 years ago
8 0

Answer:

Neither

Step-by-step explanation:

Simora [160]3 years ago
3 0
The answer to this question is neither
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2. A student usually saves $20 per month. He would like to reach a goal of saving $350 in 12 months. The student writes the equa
Zigmanuir [339]

Answer:

x = 9.17 (nearest hundredth)

The variable x is the amount the student needs to save each month in addition to his usual saved amount of $20.

Step-by-step explanation:

350 = 12(x + 20)

Multiply out brackets:  350 = 12x + 240

Subtract 240 from both sides:  110 = 12x

Divide both sides by 12:  9 1/6 = x

x = 9.17 (nearest hundredth)

The variable x is the amount the student needs to save each month in addition to his usual saved amount of $20.

3 0
2 years ago
Elaine has a piece of wire that is 2.16 meters long.Dikembe has a piece of wire that is 2.061 meters long. whose piece of wire i
vesna_86 [32]
Elaine's piece is bigger because when you look at the tenths place, you can see that 1 is bigger than 0.
4 0
3 years ago
Read 2 more answers
How do you work out 5 2/3 - 2 3/4 ???
loris [4]
Hi,
i worked out the problem and I attached the picture  

6 0
3 years ago
the ratio of boys to girls in a class is 5:4 there are 36 students in the class how many students are girls
Alina [70]
First add up the total parts in the ratio.
5 + 4 = 9
Now we need to know the value of each part
36 / 9 = 4
The girls has total of 4 parts, therefore we can just multiply the number of parts by the amount in each part
4 x 4 = 16
So there r 16 girls in the class
4 0
3 years ago
Which symbol correctly compares these two fractions?<br> 4/7 and 8/16
WITCHER [35]

Answer: 4/7 > 8/16

Step-by-step explanation:

Draw each fraction on a fraction bar (similar to a Hersey's Bar each fraction bar being the same length just broken up differently to represent each fraction) and you will see that 4/7 is bigger than 8/16.

5 0
3 years ago
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