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Karolina [17]
2 years ago
7

Worldwide, the proportion of babies who are boys is about 0.51 . Let the random variable X represent the number of boys in five

children. Find the mean and standard deviation of this random variable.
Mathematics
1 answer:
solmaris [256]2 years ago
6 0

Answer:

mean = 2.55

Standard deviation = 1.118

Step-by-step explanation:

Probability of babies who are boys

P = 0.51

Then we have q = 1-p

= 1-0.51

= 0.49

We have n = 5

We calculate the mean as:

np

= 0.51x5

= 2.55

Therefore mean = 2.55

The standard deviation

= √variance

= √npq

= √0.51x5x0.49

=√1.2495

= 1.118

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tigry1 [53]

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Afina-wow [57]

Answer:

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3 years ago
Evaluate -29 - X<br> when x = 6
notka56 [123]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
In how many ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other?
balandron [24]
The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
</span>
So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
</span>
<span>=====================================================
</span>
<span>Another solution:
</span>
<span>If ann seated in one of the ends, the number of ways = 3*2
</span>
<span>If ann didn't seat in one of the ends , the number of ways = 2*3
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So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
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The remaining persons can seat with a number of ways = 3! = 6
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7 0
3 years ago
Find the 20th term of the arithmetic sequence 15, 9, 3, -3, ...
RUDIKE [14]

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-60 + -46

-106

You're just subtracting by 6.

4 0
3 years ago
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