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Katyanochek1 [597]
1 year ago
7

Brad has the option of using three types of tables in his bagel shop: square tables with a side length of 39 inches rectangular

tables 23 inches wide and 71 inches long round (circular) tables with a diameter of 48 inches. Which type of table has the largest area?
Mathematics
1 answer:
KatRina [158]1 year ago
3 0

The type of table that has the largest area is circular table

<h3>How to find area of figures?</h3>

area of a square = l²

where

  • l = length

Therefore,

area of the square table = 39² = 1521 inches²

area of a rectangle = lw

where

  • l = length
  • w = width

Therefore,

area of the rectangular table = 23 × 71 = 1633 inches²

area of a circle = πr²

where

  • r = radius

Therefore,

area of a circular table = π × (48 / 2)² = 576π = 1808.64 inches²

Therefore, the table that has the largest area is the circular table.

learn more on area here: brainly.com/question/10506642

#SPJ1

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If p(x) = x2 – 1 and 4(x) = 5(x-1), which expression is equivalent to (p -9)(x)?
jenyasd209 [6]

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5 times 5 24

Step-by-step explanation:

6 0
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Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog. What algebraic expression could you make to find (g) which
emmasim [6.3K]

Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:

1. The word "more" indicates an Addition.

2. The word "times" indicates Multiplication.

Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:

5g

Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:

5g+6

Hence, the answer is:

5g+6

7 0
1 year ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
What is the area? (IXL)
Zina [86]

Answer:

45 square meters

Step-by-step explanation:

we know that

The area of trapezoid is equal to

A=\frac{1}{2}(b1+b2)h

where

b1 and b2 are the parallel bases

h is the height of trapezoid (perpendicular distance between the parallel bases)

we have

b1=6\ m\\b2=9\ m\\h=6\ m

substitute

A=\frac{1}{2}(6+9)6

A=45\ m^2

3 0
3 years ago
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