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nignag [31]
3 years ago
11

Arlene makes a necklace using 14 purple beads for every 6 silver beads. The necklace contains 18 beads. How many of each color b

ead are in the necklace?
Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

5.4 numbers of purple beads and 12.6 numbers of silver beads.

Step-by-step explanation:

Arlene makes a necklace using 14 purple beads for every 6 silver beads. So, she uses purple and silver beads in the ratio 14 : 6 = 7 : 3.

Now, the necklace contains 18 beads, then in the ratio 7 : 3, there will be (18 \times \frac{3}{3 + 7}) = 5.4 numbers of purple beads and (18 - 5.4) = 12.6 numbers of silver beads. (Answer)

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3 + 4ab+ 4ab - 5b + m
Rainbow [258]

Answers:  

  • Number of terms: 5
  • Coefficients:  4, 4, -5 and 1
  • Constant term:  3

===================================================

Explanation:

Each term is separated by a plus sign or a minus sign. We could rewrite the 4ab-5b portion as 4ab + (-5b) to help get everything separated by a plus sign.

The five terms are

  • 3
  • 4ab
  • 4ab
  • -5b
  • m

The coefficients are the numbers just to the left of the variable. For a term like 4ab, the coefficient is 4. For the term "m", we can think of it as 1m so we can see it has a coefficient of 1.

The constant term is the term that doesn't have any variable attached to it. That would be the "3" as the first term.

5 0
2 years ago
Suppose that circles R and S have a central angle measuring 80°. Additionally, the measure of the sector for circle R is
riadik2000 [5.3K]
The correct answer is B) 9 m.

The measure of the sector of circle R is 32π/9 m.  The measure of the central angle is 80°.  This means that the sector is 80/360 = 2/9 of the circle.  The area of a circle is given by A=πr², so the area of the sector is A=2/9πr².  To verify this, 2/9π(4²) = 2/9π(16) = 32π/9.

Using this same formula for circle S, we will work backward to find the radius:

18π = 2/9πr²

Multiply both sides by 9:
18*9π = 2πr²
162π = 2πr²

Divide both sides by 2π:
162π/2π = 2πr²/2π
81 = r²

Take the square root of both sides:
√81 = √r² 
9 = r

6 0
4 years ago
Read 2 more answers
Find sin(2x), cos(2x), and tan(2x) from the given information.
larisa86 [58]

Since \cot(x)=\frac{2}{3} and \cot^{2} x+1=\csc^{2} x, we know that:

\left(\frac{2}{3} \right)^{2}+1=\csc^{2} x\\\\\frac{13}{9}=\csc^{2} x\\\\\csc x=\frac{\sqrt{13}}{3}

If \csc x=\frac{\sqrt{13}}{3}, this means that \sin x=\frac{3}{\sqrt{13}} and by the Pythagorean identity,

\sin^{2} x+\cos^{2} x=1\\\left(\frac{3}{\sqrt{13}} \right)^{2}+\cos^{2} x=1\\\frac{9}{13}+\cos^{2} x=1\\\cos^{2} x=\frac{4}13}\\\cos x=\frac{2}{\sqrt{13}}

  • Using the double angle formula for sine, \sin(2x)=2\left(\frac{3}{\sqrt{13}} \right)\left(\frac{2}{\sqrt{13}} \right)=\boxed{\frac{12}{13}}
  • Using the double angle formula for cosine, \cos(2x)=1-2\left(\frac{3}{\sqrt{13}} \right)^{2}=\boxed{-\frac{5}{13}}
  • So, since tan=sin/cos, \tan (2x)=\frac{\sin(2x)}{\cos(2x)}=\frac{\frac{12}{13}}{-\frac{5}{13}}=\boxed{-\frac{12}{5}}

7 0
2 years ago
In ΔRST, r = 210 cm, s = 500 cm and t=560 cm. Find the measure of ∠T to the nearest 10th of a degree.
Virty [35]

Answer:

95.3

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP
jek_recluse [69]
I need points bro, so imma just type this rq cuz I’m mid test thank u tho
8 0
3 years ago
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