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3 years ago

Solve -7 2/3+(-5 1/2)+8 3/4=

Mathematics

2 answers:

fomenos3 years ago

8 0

Answer:

Exact Form: -53/12

decimal form: -4.416

mixed number -4 5/12

Step-by-step explanation:

convert mixed numbers into improper fractions: -2 3/3 +(5 1/2)+ 8 3/4

convert mixed numbers into improper fractions: =11/2 = $-\frac{23}{3}+\left(-\frac{11}{2}\right)+\frac{35}{4}$ =

$-\frac{23}{3}+\left-\frac{11}{2}\right+\frac{35}{4}$ $=-\frac{92}{12}-\frac{66}{12}+\frac{105}{12}$

$\frac{-92-66+105}{12}$

add/subtract the numbers: -92-66+105=-53

-53/12

apply the fraction rule: $\frac{-a}{b} = -\frac{a}{b\\}$

$=-\frac{53}{12}\\$

Harrizon [31]3 years ago

3 0

Answer:

-53/12

Step-by-step explanation:

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What is an equation of the line that passes through the point (-5, -6) and is

Vikentia [17]

Answer: y= 2x +4

Step-by-step explanation:

1. To be able to write the equation of the line, you want to be able to find the slope first. To do so, rearrange the given equation x+2y=2 into slope-intercept form, which is y=mx+b

First subtract x from both side, which will give us 2y=2-x. Rearrange this to get 2y= -x+2. Then, divide both sides by 2. This will give us y= -1/2x+1

2. Now that you have the equation, look for the slope in the new equation; this will be the m value. In this case, the slope is -1/2. Since we are looking for a line that is perpendicular, we have to change the slope so that it is the opposite reciprocal. The opposite reciprocal of -1/2 is 2, so the slope of the equation we want to find is 2.

3. Next, all we have to do is plug the given ordered pair (-5, -6) and the slope that we found (m=2) into the point-slope equation, which is $y-y_{1} = m(x-x_{1} )$

That will give us:

y+6 = 2(x+5)

4. Now, solve this equation.

y+6 = 2(x+5) --> distribute the 2 inside the parentheses

y+6 = 2x + 10 --> subtract 6 from both sides

y= 2x +4

4 0

3 years ago

a local basketball court dimensions are 50 ft long, 20 ft wide, the court is lost square footage by 1/4. what are the new dimens

VikaD [51]

50x20=1000

1000x(1/4)=250

1000-250=750ft^2

3 0

3 years ago

Oliver earns $9 per hour. Write and solve an equation to find how many hours he must work to earn $315

natka813 [3]

Y=9x

315=9x

315/9=x

35=x

7 0

3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago

The number of ways in which 4 squares can be chosen at random on a chess board such that they lie on a diagonal line?.

wariber [46]

The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

<h3>What are permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:

The required number of ways:

= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))

= 2[2[ 1 + 5 + 15+35] + 70]

= 364

Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ4

5 0

2 years ago