Question

Find the total surface area of this prism where the cross section is an isosceles triangle 5cm, 13cm, 24cm, 10cm

Answer 1

Answer: 620 cm2

Step-by-step explanation:

The base of the prism is a rectangle with 24 cm x 10 cm, so the base area is:  B = 24 * 10 = 240 cm2

The cross section is a triangle with base = 24 cm and height = 5 cm, so its area is:  C = 24 * 5 / 2 = 60 cm2

The sides are rectangles with 10 cm x 13 cm, so their area is:  D = 10 * 13 = 130 cm2

The total surface area is:  S = B + 2C + 2D = 240 + 2*60 + 2*130 = 620 cm2