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3 years ago

If f(x)= 5x + 4 find the inverse of f(x)

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

Answer:

f(x)=y

5x+4=y

5x=y-4

x=y-4/5

inverse of x=(x-4)/5

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Solve the equation for all real solutions in simplest form.<br> z^2 - 12z +9= -3

Mars2501 [29]

Answer:

Solving the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$ we get $\mathbf{z=10.9\: or\: z=1.1}$

Step-by-step explanation:

We need to solve the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$

First simplifying the equation:

$z^2 - 12z +9+3= -3+3\\z^2 - 12z +12= 0$

Now, we can solve the equation using quadratic formula:

$z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

we have a = 1, b=-12 and c=12

Putting values in formula and finding values of x

$z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\z=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(12)}}{2(1)}\\z=\frac{12\pm\sqrt{144-48}}{2}\\z=\frac{12\pm\sqrt{96}}{2}\\z=\frac{12\pm9.8}{2}\\z=\frac{12+9.8}{2}\:or\:z=\frac{12-9.8}{2}\\z=10.9\:or\:z=1.1$

So, we get value of z: z=10.9 or z=1.1

Solving the equation for all real solutions in simplest form.

$z^2 - 12z +9= -3$ we get $\mathbf{z=10.9\: or\: z=1.1}$

3 0

3 years ago

Help? I forgot how to do this lol I have really bad memory

pashok25 [27]

$\dfrac{2}{3} \times \dfrac{3}{4} \times \dfrac{1}{2}$

Cancel out 2, the common factor for the numerator and denominator:

$= \dfrac{1}{3} \times \dfrac{3}{4} \times \dfrac{1}{1}$

Cancel out 3, the common factor for the numerator and denominator:

$= \dfrac{1}{1} \times \dfrac{1}{4} \times \dfrac{1}{1}$

Combine into single fraction:

$= \dfrac{1 \times 1 \times 1}{1 \times 4 \times 1 } = \dfrac{1}{4}$

$\bf \text {Answer = } \dfrac{1}{4}$

8 0

3 years ago

GEOMETRY PROBLEM HELP ME PLEASE

Anon25 [30]

Answer:

18. x=31

19.x=15

20. a. x=5 WXY= 28

b. YXZ=28

c. WXZ=56

6 0

3 years ago