Answer: C
Step-by-step explanation:
Okay first set a comparison since the two triangles are similar
x-1/20=x-1+27/3x+8
x-1/20 = x+26/3x+8
cross multiply
20x+520=3x^2+8x-3x-8
3x^2-15x-528=0
3(x^2-5x-176)=0
im kinda lazy to factor this out so i used an online calculator right here but factor it out like a good kid
x=16, x=-11
it has to be positive so x=16
C
Answer:
$28
Step-by-step explanation:
The markup was 0.40×$20 = $8, so the new price is ...
$20 +8 = $28
y < - 8 or y > 4
inequalities of the form | x | > a always have solutions of the form
x < - a or x > a
we have to solve
y + 2 < - 6 or y + 2 > 6
y + 2 < - 6 ( subtract 2 from both sides )
y < - 8
or
y + 2 > 6 ( subtract 2 from both sides )
y > 4
these can be combined using interval notation
y ∈ (- ∞, - 8 ) ∪ (4, ∞ )
As a check
substitute chosen values of x from each interval
y = - 10 : | - 10 + 2 | = | - 8 | = 8 > 6 this is true
y = 12 : | 12 + 2 | = | 14 | = 14 > 6 which is also true
Add the following polynomials:
All polynomials are already ordered according to their degree (exponent), and therefore you can just add straight down in columns.
For x3: 2 + 1 - 3 = 0
For x2: -4 + 6 + 2 = 4
For x: 6 - 8 -4 = -6
Constants: -3 + 12 - 7 = 2
The answer is:
4x^2 - 6x + 2
