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koban [17]
3 years ago
9

Solve for the measure of angle G in degrees.....

Mathematics
2 answers:
defon3 years ago
8 0

Answer:

76 degrees is the answer hope this help if I'm wrong I'm so sorry

7nadin3 [17]3 years ago
7 0

Answer:

Angle G = 76 degrees

Step-by-step explanation:

66 + 2x + x = 180

66 + 3x = 180

3x = 114

x = 38

2(38) = 76

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He scatter plot shows the number of pages scanned (y) in different number of hours (x) by a scanning machine: which function bes
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Do you understand how to solve or do you want me to explain
4 0
3 years ago
03. O preço a ser pago por uma corrida de táxi inclui uma parcela fixa, denominada bandeirada, e uma parcela que depende da dist
uranmaximum [27]

Answer: d) v = 3.20 + 1.50n.

Step-by-step explanation:

Let 'v' be the price to pay in a 'n' kilometer.

Given: The price to be paid for a taxi ride includes a fixed parcel, called a flag, and a parcel that depends on the distance traveled.

Flag costs = $ 3.20 and

Each kilometre run costs = $ 1.50

Then, the amount of 'v' to pay in a 'n' kilometer race = Flag costs +   (n)× (Each kilometre run costs )

⇒ v= 3.20 + 1.50n

Hence, the correct option is  d) v = 3.20 + 1.50n.

7 0
3 years ago
Determine the value of x.
stellarik [79]
It is B 4.4
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3 0
3 years ago
10+5-7=3y<br><br> -10x+5x+5=-15<br><br> 3x+2x-4x+10<br><br> pre algebra 8th grade math
jasenka [17]

Answer:

1) y=8/3=2 2/3   2) x=4    3) x+10

Step-by-step explanation:

1) 10+5-7=3y

Calculate the sum or difference.

8=3y

Swap the sides of the equation.

3y=8

Divide both sides by 3.

y=8/3=2 2/3

2) -10x+5x+5=-15

Collect like terms.

-5x+5=-15

Move the constant to the right-hand side and change the sign.

-5x=-15-5

Calculate the difference.

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Divide both sides by -5.

x=4

3) 3x+2x-4x+10

Collect like terms.

(3+2-4)x+10

Calculate the sum or difference.

1x+10

When the term has a coefficient of 1, it doesn't have to be written.

x+10

Hope this helps :)

5 0
3 years ago
Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to
polet [3.4K]
This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 (14 x^{2}) by changing the 14 to 0. That way we'll left with f(x)=5x-1 which only has one real root:
0=5x-1
5x=1
x= \frac{1}{5}

7 0
3 years ago
Read 2 more answers
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