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2 years ago

Solve for the measure of angle G in degrees.....

Mathematics

2 answers:

defon2 years ago

8 0

Answer:

76 degrees is the answer hope this help if I'm wrong I'm so sorry

7nadin3 [17]2 years ago

7 0

Answer:

Angle G = 76 degrees

Step-by-step explanation:

66 + 2x + x = 180

66 + 3x = 180

3x = 114

x = 38

2(38) = 76

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For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

Solve for d. 13d + 4 = 43 A.3 B.13 C.39 D.None of the above

sergejj [24]

Answer is A
Because 43-4=39
39/13=3

6 0

3 years ago

Read 2 more answers

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crimeas [40]

Answer:

Step-by-step explanation:

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So 18 is the closest integer to $\sqrt{321}$

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2 years ago

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Y+7x9;x=-1,0,3

DanielleElmas [232]

Answer:

Step-by-step explanation:

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3 years ago

Tamara wants to calculate the height of a tree outside her home. Using her clinometer, she measures the angle from 35 feet away

serg [7]

Answer:

71.32 feet

Step-by-step explanation:

We set up a trigonometric function to get height of tree

Distance ,x = 35 feet away from tree base

Angle = 62⁰ at eye level

Y = tan(angle) * x

= Y = tan(62⁰) x 35

Y = 1.881 x 35

Y = 65.82 feet

We add Tamara's height to the total height of the tree

= 65.82feet + 5.5 feet

= 71.32 feet is the height of the tree

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3 years ago