<em>Your question has confusing details. So, I will rephrase as:</em>
<em>How many 2' x 4' would be needed for Bottom Plates and Double Top Plates on a Building 25' x 50' ?
</em>
<em></em>
Answer:
12.5 plates
Step-by-step explanation:
Given
Building dimension:
![Length = 25ft](https://tex.z-dn.net/?f=Length%20%3D%2025ft)
![Width = 50ft](https://tex.z-dn.net/?f=Width%20%3D%2050ft)
Plates
![Length = 2ft](https://tex.z-dn.net/?f=Length%20%3D%202ft)
![Width= 4ft](https://tex.z-dn.net/?f=Width%3D%204ft)
To do this, we have to divide the dimension of the building by the dimension of the plates
So, we have:
![n = \frac{Length\ of\ Building}{Length\ of\ Plates}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7BLength%5C%20of%5C%20Building%7D%7BLength%5C%20of%5C%20Plates%7D)
and
![n = \frac{Width\ of\ Building}{Width\ of\ Plates}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7BWidth%5C%20of%5C%20Building%7D%7BWidth%5C%20of%5C%20Plates%7D)
For the length, we have:
![n = \frac{25}{2}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B25%7D%7B2%7D)
![n = 12.5](https://tex.z-dn.net/?f=n%20%3D%2012.5)
For the width, we have:
![n = \frac{50}{4}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B50%7D%7B4%7D)
![n = 12.5](https://tex.z-dn.net/?f=n%20%3D%2012.5)
So, 12.5 of the plates are needed
Answer:
24 cm
Step-by-step explanation:
Let the length of other base be x cm
Therefore, by mid segment formula of a trapezoid, we have:
![23 = \frac{1}{2} (x + 22) \\ \\ 23 \times 2 = x + 22 \\ 46 = x + 22 \\ 46 - 22 = x \\ x = 24 \: cm](https://tex.z-dn.net/?f=23%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%28x%20%2B%2022%29%20%5C%5C%20%20%5C%5C%2023%20%5Ctimes%202%20%3D%20x%20%2B%2022%20%5C%5C%2046%20%3D%20x%20%2B%2022%20%5C%5C%2046%20-%2022%20%3D%20x%20%5C%5C%20x%20%3D%2024%20%5C%3A%20cm)
Independent is number of tickets bought. dependent is total cost.
y=60x
Answer:
j= 12
Step-by-step explanation:
j = 36/3
j = 12