Answer:
1. 2x^2+6x=0 <--> 2x(x+3)=0
2.4x-x^2=0 <--> x(4-x)=0
3.14x-7x^2=0 <--> 7x(2-x)=0
4.24x-6x^2=0 <--> 6x(4-x)=0
Step-by-step explanation:
just try to expand the answer given for example when you look at no.1, 2x•x=2x^2 so look for the equation where there is a 2x^2 in it.
for finding the solution, for example when you look at no.1 again, you have 2x=0 so x=0/2=0 and you also have x+3=0 so x=-3
this applies to all the pther no.
