Answer:
f(n) = 74 + 11(n - 1)
<u>For the 7th term</u>
n = 7
f(7) = 74 + 11(7 - 1)
= 74 + 11(6)
= 74 + 66
<h2>= 140</h2>
<u>For</u><u> </u><u>the</u><u> </u><u>8</u><u>t</u><u>h</u><u> </u><u>ter</u><u>m</u>
n = 8
f(8) = 74 + 11( 8 - 1)
= 74 + 11(7)
= 74 + 77
<h2 /><h2>= 151</h2>
Hope this helps you
First you have to make the assumption that these are the only two outcomes. There is also the possibility of hitting the ball and getting out.
However, if we assume that these are the only two cases, we know that the probability is 58.3%. This is because it has been on base 7 times out of 12.
Answer:
26 seats
Step-by-step explanation:
10+10=20 +6 =26
5. (X,y)=(7,23)
One solution
Answer:
Five less than -20 is -25
Step-by-step explanation: