Answer:
The average cost of each tie is $56.350
Step-by-step explanation:
We are given that a men tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties
So, Cost of 450 ties = 
An order for 100 ties that cost $20.00 each
Cost of 100 ties = 
Total cost price = 17995.5+2000 = 19995.5
Let the selling price of 1 tie be x
Total ties = 450+100 = 550
So, SP of 550 ties =550x
Now we are given that markup is 55%
So, Profit % = 55%
So, 
Substitute the values





Hence The average cost of each tie is $56.350
2sinxcosx - sin(2x)cos(2x) = 0
<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>
<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>
<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>
<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>
<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>
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The value of angle x of the given cyclic segment is; 49.5°
<h3>How to find the angle of an arc?</h3>
We are given the measure of the angle of arc QS as (4x – 18)°
Now, to find the measure of arc QS, this angle is to be equal to 180° and as such;
Thus;
(4x – 18)° = 180°
4x - 18 = 180
4x = 180 + 18
4x = 198
x = 198/4
x = 49.5°
The angle subtended by the arc at the center of a circle with center C is the angle of the arc. It is denoted by. m AB, where A and B are the endpoints of the arc. With the help of the arc length formula, we can find the measure of arc angle.
The formula to measure the length of the arc is;
Arc Length Formula (if angle θ is in degrees); s = 2πr (θ/360°)
Arc Length Formula (if θ is in radians) s = ϴ × r.
Thus, the value of x of the given cyclic segment is; 49.5°
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Answer:
16:10, 4:2.5, 24:15
Step-by-step explanation:
i multiplied each value by 2 and 3 and on the second one i divided by 2
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Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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