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AleksandrR [38]
3 years ago
5

$70,000 - 17 1/2 % . if i get this right i get the iphone xr​

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

$57750

Step-by-step explanation:

$70,000 - 17.5%

17.5 % = .175

.175 * $70000 = $12250

$70000 - $12250 = $57750

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(x+40)° what is x? plssss help meee thank you !!
SVEN [57.7K]

Answer:

I got 103˚ because I put (x+40)˚ into the calculator

5 0
3 years ago
Someone told me the answer was 39?? Is this true? Why ? please help.
Ira Lisetskai [31]
The problem has the equation:

f(x) = (3) ^ (x/2)

In order to get the average increase in the number of flowers being pollinated from day 4 to day 10, then we need to use the equation substituting x with 4 to 10

f(4) = 9
f(5) = 12.59
f(6) = 27
f(7) = 46.77
f(8) = 81
f(9) = 140.30
f(10) = 243

Then add all the values and divide it by 7
 = 559.66 / 7
= 79.95

So the correct answer is 79.95
8 0
3 years ago
Peter is a 40-year-old average income earner. He is ready to start planning for retirement, and plans to make the maximum possib
Bad White [126]
Roth IRA doesn't get you a tax deduction for the contributions, but the earnings grow tax free and you don't pay tax on the withdrawals after retirement. A traditional IRA gives you a tax deduction for the contributions at the time you make them, and the earnings grow tax free, but when you withdraw the money after retirement, you are taxed on it. The idea is that you are hopefully in a lower tax bracket at that point. So its only natural that Roth IRA is the best.
6 0
3 years ago
Please someone help me I’m confused
insens350 [35]

Answer:

a2 =14

a4 = 22

a11 = 50

Step-by-step explanation:

an = 10 + (n-1) *4

n is the term number

Let n =2

a2 = 10 +(2-1)*4 =10 +(1)*4 = 14

Let n =4

a4= 10 + (4-1)*4 = 10 *3*4 = 10+12 = 22

Let n = 11

a11 = 10 +(11-1)*4 = 10 *10*4 = 10+40 = 50

4 0
3 years ago
Square roots in trigonometry. I don’t understand please help?
cupoosta [38]

By definitions of the (co)tangent and cosecant function,

3\tan^2x-2=\csc^2x-\cot^2x\iff3\dfrac{\sin^2x}{\cos^2x}-2=\dfrac1{\sin^2x}-\dfrac{\cos^2x}{\sin^2x}

Turn everything into fractions with common denominators:

\dfrac{3\sin^2x-2\cos^2x}{\cos^2x}=\dfrac{1-\cos^2x}{\sin^2x}

Recall that \cos^2x+\sin^2x=1, so we can simplify both sides a bit.

On the left:

\dfrac{3\sin^2x+3\cos^2x-5\cos^2x}{\cos^2x}=\dfrac{3-5\cos^2x}{\cos^2x}

On the right:

\dfrac{1-\cos^2x}{\sin^2x}=\dfrac{\sin^2x}{\sin^2x}=1

(as long as \sin x\neq 0, which happens in the interval 0\le x\le\pi when x=0 or x=\pi)

So we have

\dfrac{3-5\cos^2x}{\cos^2x}=1\implies3-5\cos^2x=\cos^2x

\implies3=6\cos^2x

\implies\cos^2x=\dfrac12

\implies\cos x=\pm\dfrac1{\sqrt2}

\implies x=\dfrac\pi4\text{ or }x=\dfrac{3\pi}4

4 0
3 years ago
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