Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that 
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So
You must survey 784 air passengers.
We can first convert 9.5 into fraction :
9.5= 9 1/2
Then we can use deduction to find out the answer:
9 1/2 - 6 1/3
=19/2 - 19/3
We change it to the same denominator:
=19×3/6 - 19×2/6
= 57/6 - 38/6
= 19/6
Therefore there are 19/6 or 3 1/6 gallons left in the tank.
Hope it helps!
So for this problem you know that 15 is 1/4 of an hour so to get the amount of papers each individual could deliver by themselves in an hour you would multiply the amount they can deliver in 15 minutes by 4. Denny delivers 6 so multiplying that by 4 is 24. Next Brendan delivers 5 in 15 minutes so multiplying that by 4 you get 20. The final step is to add 20 and 24 to get the total amount of papers between the two of them that gets delivered in an hour. This will result in your answer of 44.
Remember your Number system
After the decimal point to the right, the next digit is the TENTH, and next is HUNDREDTH.
So for 26.5 = 26.500.
The tenth digit is 5, and the Hundredth is 0.
After the hundredth digit which is 0, the next digit is also 0.
The second 0 is not up to 5, so we would not add to the first zero.
(Was it 5, or above, we would have added 1 to first zero)
So the answer is 26.50. If the next digit after the hundredth digit was 5 or more the answer would have been 26.51.
But for this question the answer is 26.50 to the nearest hundredth. Cheers.
