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UkoKoshka [18]
3 years ago
13

M is the midpoint of GR, G has coordinates ( -8,3) and M is at the origin. Find the coordinates of R

Mathematics
1 answer:
mars1129 [50]3 years ago
6 0

Since M is the midpoint and has the coordinate (0, 0), therefore the distance of G to M and R to M must be equal. This also means that point M is the average of the coordinates of G and R. Therefore:

(x + -8) / 2 = 0

x = 8

 

(y + 3) / 2 = 0

y = -3

 

<span>Therefore point R is located at (8, -3).</span>

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Does someone want to help me solve this problem
Hoochie [10]

Answer:

(cx)2-(dy) 2

Step-by-step explanation:

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A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base
timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)²  +  (y/b)²   -  (z/c)²  =  1                         (1)

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We can express equation (1)

(x/a)²  +  (y/b)²    =  (z/c)² + 1                 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for  z = k       ( K = 1 , 2 , 3  and so on ) circles of different radius

(x/a)²  +  (y/b)²    =  (k/c)² + 1

at z = k = 0 at the base of the hyperboloid  d = 300   or r = 150 m

we have

(x/a)²  +  (y/b)²   = 1      

x²  +  y²   =   a²                a² = (150)²       a = b = 150

and    x²  +  y²  = (150)²

Now the other condition is at 200 m above the base d = 500 m   r = 250 m  minimum diameter then in equation (2)  we have:

(x/a)²  +  (y/b)²    =  (z/c)² + 1        

(1/a)² [ x² + y² ]  = (z/c)² + 1  

but   x²  +  y²  = r²    and in this case   r  =  250 m  then

(250)²/(150)²   =  (z/c)² + 1    ⇒ (62500/ 22500)  =  (200/c)² + 1

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2.78c²  =  40000  + c²

1.78c² = 40000

c²  =  40000/1.78

c²  = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)²   + y² /(150)² - z²/149,91  = 1

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juin [17]

Answer:

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Step-by-step explanation:


6 0
2 years ago
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