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3 years ago

If A and B are sets and AUB=A∩B ,then which of the following true for A and B

Mathematics

1 answer:

stich3 [128]3 years ago

6 0

Answer:

A=B

Step-by-step explanation:

If AUB=A∩B then both A and B contain the values both have hence they're equal

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There are 7 red 3 green 2 blue and 8 purple marbles in a bag if a marble is randomly chosen 250 times predict how many times it

kati45 [8]

Answer:

It should be red or green 125 times

Step-by-step explanation:

The first thing to do here is to calculate the probability of selecting a red or a green marble

Total number of marbles = 7 + 3 + 2 + 8 = 20

Probability of selecting a red marble is 7/20

Probability of selecting a green marble is 3/20

The probability of selecting a red or a green marble = Probability of selecting a red marble + Probability of selecting a green marble = 7/20 + 3/20 = 10/20 = 1/2

Now our selection spans 250 times, the number of times it should have been a green or a red marble = The probability of selecting a green or a red marble * number of selection times = 1/2 * 250 = 125 times

3 0

3 years ago

In a Match 6 Lotto, winning the jackpot requires that you select six different numbers from 1 to 49, and that the same six numbe

zimovet [89]

Answer:

$P=\frac{1}{13,983,816}=7.2\ x\ 10^{-8}$

Step-by-step explanation:

Consider the following characteristics of the problem:

The numbers that are selected are different between 1 and 49. This means that the same number is not repeated twice.

The order in which the selected numbers appear does not matter:

This means that (123) = (312)

With this in mind, we know that it is a problem of combinations without repetition. It is not calculated using permutations because in the permutations the order of selection is important, for example: (123) is not equal to (312)

The formula for calculating combinations without repetition is:

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the number of "elements" you can choose and choose r from them

In this case:

n=49

r=6

So:

$49C6=\frac{49!}{6!(49-6)!}$

$49C6=13,983,816\ outcomes$

There are 13,983,816 possible results

This is the best method to calculate the number of possible outcomes.

<em><u>"Besides your method, is there another method to determine the number of outcomes?"</u></em>

Sure, make a list of the 13,983,816 different sets of 6 numbers.

To win it is necessary to obtain the 6 winning numbers in any order. The number of ways this can occur is calculated by combining 6 in 6

$6C6=\frac{6!}{6!(6-6)!}=1$

Finally the probability of winning is:

$P=\frac{1}{13,983,816}=7.2\ x\ 10^{-8}$

Note that the probability of winning is very close to 0. It is practically impossible to win the lottery, you will probably never win anything. Therefore it is better not to invest money in this

6 0

3 years ago

Joe bought g: gallons of gasoline for $2.85 per gallon and c: cans for oil for 3.15 dollars.

OlgaM077 [116]

A) 2.85g+3.15c
B)2.85(8.4)+3.15(6)=$42.84

8 0

3 years ago

help please, I have to do it before my class starts its at 10:25 and its 6:21 rn so :) I'm trying to get it done tyyyy

Radda [10]

Ii is the top left and iv is bottom right

7 0

3 years ago