Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH
Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees
Recall that mHFG + mACB = 90 degrees
Thus, mHFG + mACB = mHFG + mDFH
Therefore, mACB = mDFH.
Answer:
answer is -6=9
Step-by-step explanation:
Answer:
f(9)= -72
g(-9)= 225
Step-by-step explanation:
First put the original equation
f(x)=-7x-9
Next plug in the number f(9)
f(9)=-7(9)-9
After multiply -7(9) which gets you -63
f(9)=-63-9
Then subtract -63-9 which gets you -72
f(9)=-72
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First put the original
g(x)=6x3-23x
Next plug in the number g(-9)
g(-9)=6x3-23(-9)
After multiply 6x3 which gives you 18 then multiply -23(-9)
g(-9)=18+207
then add 18+207 which gives you 225
g(-9)=225
Answer:
B. fifty divided by the sum of 5 and n
Step-by-step explanation:
Step-by-step explanation:
We are told that for a large data set of a average student grades, the third quartile Q3 is found 78.5.
Since we know that third quartile represents the number such that 75% of the data is less than this number. Third quartile is the middle value between median and the highest value of a data set. Third quartile is also known as upper quartile. Third quartile splits lower 75% data from highest 25% of data.
Therefore, third quartile represents that 75% of student grades are less than 78.5 and 25% of students grades are greater than 78.5.