All categories

3 years ago

Solve the equation -6x-3y=-21 and 3x+y=6 by.combining the equations

Mathematics

1 answer:

Firlakuza [10]3 years ago

7 0

Answer:

i have made it in above picture hope it helps

You might be interested in

Please help 70 Brainly points thanks

Cloud [144]

Answer:

9) x=58

10) r=4

11) m=4

12) p=3

13) x=6

14) x=-3

15) s=400

Step-by-step explanation:

9) x+2/5=12

x5 x5

x+2=60

-2 -2

x=58

10) 7r + 14 - 3r =30

-14 -14

7r-3r=16

4r=16

÷4 ÷4

r=4

11) $\frac{4}{5}$ m+2=6

-2 -2

$\frac{4}{5}$ m=4

÷ $\frac{4}{5}$ ÷ $\frac{4}{5}$

m=4

12) 2(5p+9)=48

10p+18=48

-18 -18

10p=30

÷10 ÷10

p=3

13) 5(2x-8)=20

10x-40=20

+40 +40

10x=60

÷10 ÷10

x=6

14)6(3-2x)=54

18-12x=54

-18 -18

-12x=36

÷-12 ÷-12

x=-3

15) $\frac{2s}{5}$ - $\frac{s}{2}$ =40

x5 x5

2s- $\frac{s}{2}$ =200

x2 x2

2s-1s=400

1s=400

÷1 ÷1

s=400

6 0

3 years ago

Read 2 more answers

What is 2/3x=2y+6 in ax+by=c form?

kifflom [539]

Answer:

2x - 6y = 18

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

$\frac{2}{3}$ x = 2y + 6

Multiply through by 3 to clear the fraction

2x = 6y + 18 ( subtract 6y from both sides )

2x - 6y = 18 ← in standard form

8 0

3 years ago

PLEASE HELP see picture 66 pts LOGARITHMIC

Nostrana [21]

Ln(x) should be the answer

4 0

3 years ago

Two real solutions of tx^2+3x_7=0

Olegator [25]

The number of solutions of a quadratic equation

ax^2+bx+c=0

Depends on its discriminant

/Delta=b^2-4ac

If /Delta>0 there are two distinct solutions

If /Delta=0 there are two coincident solutions

If /Delta<0 there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

The number of solutions of a quadratic equation

Depends on its discriminant

If there are two distinct solutions

If there are two coincident solutions

If there are no solutions.

We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:

b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]

3 0

3 years ago

The owner of a grocery store wants to mix two kinds of condy together to make 15lb that he can sell for $5.00 per lb. He wants t

ankoles [38]

Answer: 6 pounds of sugar candy, and 9 pounds of chocolate candy.

Step-by-step explanation:

Let's define the variables:

C = pounds of chocolate candies used.

S = pounds of sugar candies used.

We know that he wants to make a total of 15lb, then:

C + S = 15

We also want that the price per pound to be equal to 5$.

This means that the price of the 15 pounds will be the same as the price of the un-mixed candies.

C*$7.00 + $2.00*S = $5.00*15

Then we have a system of equations:

C + S = 15

C*$7.00 + $2.00*S = $5.00*15

To solve this system, we need to start by isolating one of the variables, i will isolate C in the first equation:

C = 15 - S

now we can replace that in the other equation:

(15 - S)*$7.00 + $2.00*S = $5.00*15

Now we can solve this for S.

$105 - $5.00*S = $75

$105 - $75 = $5.00*S

$30 = $5.00*S

$30/$5 = S = 6

Then there are 6 pounds of sugar candy, and we can use the equation:

C + S = 15

C + 6 = 15

C = 15 - 6 = 9

There are 9 pounds of chocolate candy in the mix.

3 0

3 years ago

Read 2 more answers