All categories

3 years ago

True or false all numbers have a decimal point we just don't write them for whole numbers

Mathematics

2 answers:

Ivanshal [37]3 years ago

8 0

uhhhhhhh itssss false

stellarik [79]3 years ago

6 0

Answer:

False

Whole numbers are wholes, they will never ever have decimal points.

You might be interested in

Can somebody please help me with this and explain it?

taurus [48]

Answer:

7. No, because the x-value 11 has two y-values pair with it.

8. Not a function

Step-by-step explanation:

If there is more than one y-values per x-value then it is not considered a function, same with Question 8.

5 0

3 years ago

Read 2 more answers

B. 135: 90<br> Simplify the ratio

icang [17]

Answer: 3/2

Divide both 135 and 90 by 45 and you get 3 and 2

5 0

3 years ago

Read 2 more answers

Write an equation, in point-slope form, of the line that passes through the point (4, -3) with a slope -7.

Ilya [14]

Answer:

point-slope form:

y - 10 = -4(x - -2)

y - 10 = -4(x + 2)

---

slope-intercept form:

y - 10 = -4x - 8

y = -4x - 8 + 10

y = -4x + 2

Step-by-step explanation:

6 0

3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

4 years ago

FIRST ANSWER GETS BRAINLIEST!!!

nlexa [21]

Answer: B

Step-by-step explanation:

169 = 144 + 25

Hyp^2 = opp^2 + adj^2

13^2 = 12^2 + 5^2

6 0

4 years ago

Read 2 more answers