We want to solve the Initial Value Problem y' = y + 4xy, with y(0) = 1.
To use Euler's method, define
y(i+1) = y(i) + hy'(i), for i=0,1,2, ...,
where
h = 0.1, the step size.,
x(i) = i*h
1st step.
y(0) = 1 (given) and x(0) = 0.
y(1) ≡ y(0.1) = y(0) + h*[4*x(0)*y(0)] = 1
2nd step.
x(1) = 0.1
y(2) ≡ y(0.2) = y(1) + h*[4*x(1)*y(1)] = 1 + 0.1*(4*0.1*1) = 1.04
3rd step.
x(2) = 0.2
y(3) ≡ y(0.3) = y(2) + h*[4*x(2)*y(2)] = 1.04 + 0.1*(4*0.2*1.04) = 1.1232
4th step.
x(3) = 0.3
y(4) ≡ y(0.4) = y(3) + h*[4*x(3)*y(3)] = 1.1232 + 0.1*(4*0.3*1.1232) = 1.258
5th step.
x(4) = 0.4
y(5) ≡ y(0.5) = y(4) + h*[4*x(4)*y(4)] = 1.258 + 0.1*(4*0.4*1.258) = 1.4593
Answer: y(0.5) = 1.4593
Answer:
y=(-4/3)x
Step-by-step explanation:
you put the points into this equation to find the slope
(y2-y1)/(x2-x1)
now lets label the points
(6,-8)
x1=6 and y1=-8
(3,-4)
x2=3 and y2=-4
Input into equation
(-4-(-8))/(3-6)=
(-4+8)/(3-6)
4/-3
Answer:
This question is very big, you should shorten your question a bit so that I can answer it quickly, the rest is just that I did not understand the question a bit
Answer:
47
Step-by-step explanation:
this is due to when 286 is divided by 61 it gets 40 and the remainder gets you 7 as a result it is 47
